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Chapter 6 Notes

# Chapter 6 Notes - ∙ B aluminum c=0.900 J g K ∙ C gold...

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10/1/08 CT#2: For a given reaction, H<0. Which of the following is correct? A) Heat is a reactant B) The products are less stable than the reactants C) The reaction is endothermic D) The products have lower enthalpy than the reactants Calorimetry: Determine H by measuring heat flow (q) Q (is proportional to) T q/ T=H.C.=heat capacity of an object (J/K) q/mass T=c=specific heat capacity (J/g K) ∙∆ q=c m T ∙ ∙∆ q/mol T=C=molar heat capacity (J/mol K) ∙∆ CT #3: The same amount of heat is added to 1g samples of the following substances. Which has the greatest increase in T? A) water, c=4.184 J/g K

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Unformatted text preview: ∙ B) aluminum, c=0.900 J g K ∙ C) gold, c=0.129 J/g K ∙ CT#4: Calculate q when 10.0 g of aluminum is heated from 20 to 30 degrees Celcius (c=0.90 J/g K) ∙ A) 90 J B) 145 J C) 9.0 J D) 14.5 J Calorimeter: • Figure 6.10 Constant P calorimeter q p = H ∆ • Figure 6.11 Constant V calorimeter a v = E ∆ • A calorimeter has a heat capacity of 50.0 J/K 0.050 mol HCl + 0.050 mol NaOH T o 100.0g H 2 T i = 25.00 degrees Celsius T f + 30.98 degrees Celsius-q sys =q surr-q sys =q H20 + q calorimeter =4.184 J/g K (100g)(5.98K) ∙ +50 J/K (5.98 K)-q sys =2.80 x 10 3 J...
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Chapter 6 Notes - ∙ B aluminum c=0.900 J g K ∙ C gold...

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