CSC_226_Midterm_5

CSC_226_Midterm_5 - b(0 ∙ a bn ∙(0 ∙ 0 bn ∙ 0 b...

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9. Matrix A: a n 0 0 b n P(n) : . a. b( An = ) Domain : {n| n ≥ 1} a 0 0 b Basis: P(1) : A = a n 0 0 b n a 0 0 b Proof: P(n + 1) : . a. b( × = An A × ) ( an ∙ a) + (0 ∙ 0) ( an ∙ 0) + (0 ∙
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Unformatted text preview: b) (0 ∙ a) + ( bn ∙ (0 ∙ 0) + ( bn ∙ 0) b) Matrix × An A = ( a n + ) 1 ( b n + ) 1 Matrix ( + )= A n 1...
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CSC_226_Midterm_5 - b(0 ∙ a bn ∙(0 ∙ 0 bn ∙ 0 b...

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