hw 13 - shah (rps587) HW 13 Kleinman (58225) This print-out...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
shah (rps587) – HW 13 – Kleinman – (58225) 1 This print-out should have 26 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. This HW covers Chs. 18, 19. 001 10.0 points A water hose 2 . 23 cm in diameter is used to fll a 26 L bucket. One liter is equal to 1000 cm 3 . IF it takes 1 . 85 min to fll the bucket, what is the speed at which the water leaves the hose? Correct answer: 59 . 9724 cm / s. Explanation: Let : r = 1 . 115 cm , V = 26 L , and t = 1 . 85 min . The cross-sectional area oF the hose is A = π r 2 = π (1 . 115 cm) 2 = 3 . 90571 cm 2 . According to the data given, the ±ow rate is equal to q = V t = 26 L 1 . 85 min min 60 s 10 3 cm 3 L = 234 . 235 cm 3 / s . Equating this to the product oF the velocity oF the water v and the cross-sectional area oF the hose A gives v A = q . Solving For v yields v = q A = 234 . 235 cm 3 / s 3 . 90571 cm 2 = 59 . 9724 cm / s . 002 10.0 points A 1 . 3 m wide by 2 . 1 m long water bed weighs 1084 N. ²ind the pressure that the water bed exerts on the ±oor. Assume that the entire lower surFace oF the bed makes contact with the ±oor. Correct answer: 397 . 07 Pa. Explanation: Let : W = 1084 N , w = 1 . 3 m , and = 2 . 1 m . P = W A = W w ℓ = 1084 N (1 . 3 m) (2 . 1 m) = 397 . 07 Pa . 003 10.0 points Blood oF density 604 kg / m 3 that is to be ad- ministered to a patient is raised about 1 . 03 m higher than the level oF the patient’s arm. How much greater is the pressure oF the blood than it would be iF the container were at the same level as the arm? The acceleration oF gravity is 9 . 8 m / s 2 . Correct answer: 6096 . 78 Pa. Explanation: Let : ρ = 604 kg / m 3 , h = 1 . 03 m , and g = 9 . 8 m / s 2 . Δ P = ρg h = (604 kg / m 3 ) (9 . 8 m / s 2 ) (1 . 03 m) = 6096 . 78 Pa . keywords: 004 (part 1 oF 2) 10.0 points In a machine shop, a hydraulic liFt is used to raise heavy equipment For repairs. The sys- tem has a small piston with a cross-sectional area oF 0 . 045 m 2 and a large piston with a cross-sectional area oF 0 . 234 m 2 . An engine weighing 3500 N rests on the large piston.
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
shah (rps587) – HW 13 – Kleinman – (58225) 2 What force must be applied to the small piston in order to lift the engine? Correct answer: 673 . 077 N. Explanation: Let : A 1 = 0 . 045 m 2 , A 2 = 0 . 234 m 2 , and F 2 = 3500 N . The pressure is the same, so F 1 A 1 = F 2 A 2 F 1 = A 1 F 2 A 2 = (0 . 045 m 2 ) (3500 N) 0 . 234 m 2 = 673 . 077 N . 005 (part 2 of 2) 10.0 points If the engine rises 0 . 266 m, how far does the smaller piston move? Correct answer: 1 . 3832 m. Explanation: Let : d 2 = 0 . 266 m . A hydraulic lift is eFectively 100% e±cient, so W in = W out F 1 d 1 = F 2 d 2 d 1 = F 2 d 2 F 1 = (3500 N) (0 . 266 m) 673 . 077 N = 1 . 3832 m .
Background image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 05/07/2009 for the course PHY 58225 taught by Professor Klienman during the Spring '09 term at University of Texas at Austin.

Page1 / 9

hw 13 - shah (rps587) HW 13 Kleinman (58225) This print-out...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online