Unformatted text preview: AB and line BC is equal to line BA, then lines AC and BC are equal. [C.N. 1] 9. Therefore lines AB, BC and CA are equal to one another. [C.N. 1] 10. Therefore triangle ABC is and equilateral triangle constructed on straight line AB. [Def. 20] Part II. The proof makes the assumption that the two circles cross at exactly a point where they pass directly over the centre of the other circle which would make this proof correct. Also, the proof assumes that the two circles are the same size. If the circles were not the same size or they did not pass directly over the other’s centre, this proof would be incorrect....
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This note was uploaded on 04/30/2009 for the course PHI 108 taught by Professor Hesse during the Fall '08 term at SUNY Stony Brook.
- Fall '08