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1.
: 
=

We know the equation y y1 m x x1
2.
here
=
,
= ,
m 34 and x1 y1 1 1
3.
so the equation is :
( )=
/ (  )
y 1
3 4 x 1
+ =

y 1 34x 34
=
 
y 34x 1 34
=

,
y 34x 74
it is the required equation
4.
,
= ,
,
=
 , 
given x1 y1
5 1 and x2 y2
2
3
5.
so slope
=


= +  + = 
m
y2 y1x2 x1
3 1 2 5
23
6.
: 
=

We know the equation y y1 m x x1
+ = 
+
y 1
23x 5
= 


y
23x 103 1
= 

,
y
23x 133
it is the required equation
7.
,
=
, 
,
=
,
Given x1 y1 16
13 and x2 y2 56 3
8.
so slope
=


= +

=
=
m
y2 y1x2 x1 3 1356 16
10346 5
9.
: 
=

We know the equation y y1 m x x1
10.
+
= =

y 13
5 x 16
=


y 5x 56 13
=

,
y 5x 76
it is the required equation
11.
: +
=
Given equation x 3y 2
=  +
3y
x 2
= 
+
y
13x 23
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= 
,
here slope
13
so slope of the parallel line will
,
= 
also be m
13
and (x1,y1) = (7,9)
: 
=

So the equation of the parallel line y y1 m x x1
 = 

y 9
13 x 7
= 
+
+
y
13x 73
9
= 
+
y
13x 343
12.
:
=
+
Given equation 3x 5y 9
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This note was uploaded on 04/30/2009 for the course INEQUALLIT mat116 taught by Professor Nome during the Spring '09 term at Uni. Plymouth.
 Spring '09
 nome

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