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week6solved

# week6solved - 1 We know the equation:y-y1=m x-x1 here m=34...

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1. : - = - We know the equation y y1 m x x1 2. here = , = ,- m 34 and x1 y1 1 1 3. so the equation is : -(- )= / ( - ) y 1 3 4 x 1 + = - y 1 34x 34 = - - y 34x 1 34 = - , y 34x 74 it is the required equation 4. , =- ,- , = - , - given x1 y1 5 1 and x2 y2 2 3 5. so slope = - - =- + - + = - m y2 y1x2 x1 3 1 2 5 23 6. : - = - We know the equation y y1 m x x1 + = - + y 1 23x 5 = - - - y 23x 103 1 = - - , y 23x 133 it is the required equation 7. , = , - , = , Given x1 y1 16 13 and x2 y2 56 3 8. so slope = - - = + - = = m y2 y1x2 x1 3 1356 16 10346 5 9. : - = - We know the equation y y1 m x x1 10. + = = - y 13 5 x 16 = - - y 5x 56 13 = - , y 5x 76 it is the required equation 11. : + = Given equation x 3y 2 = - + 3y x 2 = - + y 13x 23

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= - , here slope 13 so slope of the parallel line will , = - also be m 13 and (x1,y1) = (7,9) : - = - So the equation of the parallel line y y1 m x x1 - = - - y 9 13 x 7 = - + + y 13x 73 9 = - + y 13x 343 12. : = + Given equation 3x 5y 9 = - 5y 3x 9 = - y 35x 95 = here slope 35 so slope of the parallel lne will also = : , =- , be 35and the point given x1 y1 2 8 : - = - So the equation of the parallel line y y1 m x x1 - = + y 8 35x 2 = + + y 35x 65 8 = + , y 35x 465 it is the required equation 13.
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