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1C_Fall2008_MT2sols

1C_Fall2008_MT2sols - Midterm 2 Fall 2008 Physics 1C R...

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Midterm 2 – Fall 2008 Physics 1C, R. Richard Friday, November 14 SOLUTIONS
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Selected Constants Permittivity of Free Space 2 2 12 0 m N / C 10 85 . 8 × = ε 2 2 9 0 C / m N 10 99 . 8 4 / 1 × = πε Permeability of free space m/A T 10 4 7 0 × = π μ Speed of light in a vacuum c = 3.00 × 10 8 m/s Quadratic formula The solutions to are 0 2 = + + c bx ax a ac b b x 2 4 2 ± =
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Problem 1 An object is placed 80.0 cm in front of a converging lens of focal length 40.0 cm, which is 160.0 cm from a plane mirror. O (15 pts.) a) Where is the final image measured from the lens (the distance from the lens and whether it on the right or left of the lens) that would be seen by the eye looking toward the mirror through the lens? To be seen by someone looking at the mirror through the lens, light must pass through the lens from left to right, reflect at the mirror, and then pass through the lens a second time from right to left. The optic-image relationship must be applied three times. First pass through lens. The object distance is 80.0 cm and the focal length is 40.0 cm. 1 1 1 1 1 s f s = cm 0 . 80 1 cm 0 . 40 1 1 1 = s This gives (to the right of the lens) cm 0 . 80 1 = s Reflection in mirror: Because the mirror is flat, the radius of curvature and the focal length are infinite. The object distance s 2 = 160.0 cm - 80.0 cm = 80.0 cm.
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