HW1_solution

HW1_solution - T AB =(e AB T )e AB. Thus, T AB...

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MAE 101 (Spring 2009) Homework #1 Solution (Due April 9 th , 2009) Ch 2 : 58, 97, 123, 142, 159 Ch 3 : 35, 48, 56, 76, 84
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The component of T parallel to AB is given by
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Unformatted text preview: T AB =(e AB T )e AB. Thus, T AB =[(482)(-0.6) + (60.2)(0) + (-120)(0.8)](-0.6 i +0 j +0.8 k ) = -385.2(-0.6 i +0 j +0.8 k )= 231.12 i +-308.16 k N. 357 N...
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This note was uploaded on 04/30/2009 for the course MAE 210306200 taught by Professor Chatterjee during the Spring '09 term at UCLA.

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HW1_solution - T AB =(e AB T )e AB. Thus, T AB...

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