Fundamentals of Microelectronics

Info iconThis preview shows pages 1–13. Sign up to view the full content.

View Full Document Right Arrow Icon
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 2
10.3 (a) Looking into the collector of Q 1 , we see an inFnite impedance (assuming I EE is an ideal source). Thus, the gain from V CC to V out is 1 . (b) Looking into the drain of M 1 , we see an impedance of r o 1 + (1 + g m 1 r o 1 ) R S . Thus, the gain from V CC to V out is r o 1 + (1 + g m 1 r o 1 ) R S R D + r o 1 + (1 + g m 1 r o 1 ) R S (c) Let’s draw the small-signal model. r π 1 + v π 1 v out g m 1 v π 1 r o 1 v cc v out = v π 1 v out = p g m 1 v π 1 + v cc v out r o 1 P r π 1 = p g m 1 v out + v cc v out r o 1 P r π 1 v out p 1 + g m 1 r π 1 + r π 1 r o 1 P = v cc r π 1 r o 1 v out v cc = r π 1 r o 1 ± 1 + β + r π 1 r o 1 ² = r π 1 r o 1 (1 + β ) + r π 1 (d) Let’s draw the small-signal model. + v gs 1 v out R S g m 1 v gs 1 r o 1 v cc
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
v out = v gs 1 v out = p g m 1 v gs 1 + v cc v out r o 1 P R S = p g m 1 v out + v cc v out r o 1 P R S v out p 1 + g m 1 R S + R S r o 1 P = v cc R S r o 1 v out v cc = R S r o 1 ± 1 + g m 1 R S + R S r o 1 ² = R S r o 1 (1 + g m 1 R S ) + R S
Background image of page 4
Background image of page 5

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 6
Background image of page 7

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 8
10.8 π/ω π/ω t 0 . 2 I 0 R C 0 . 8 I 0 R C I 0 R C 1 . 8 I 0 R C 2 I 0 R C V X ( t ) V Y ( t ) X and Y are not true diferential signals, since their common-mode values difer.
Background image of page 9

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
10.9 (a) V X = V CC I 1 R C V Y = V CC ( I 2 + I T ) R C π/ω π/ω t V CC I T R C V CC 2 I 0 R C V CC (2 I 0 + I T ) R C V CC I 0 R C V CC ( I 0 + I T ) R C V CC V X ( t ) V Y ( t ) (b) V X = V CC ( I 1 I T ) R C V Y = V CC ( I 2 + I T ) R C
Background image of page 10
π/ω π/ω t V CC I T R C V CC (2 I 0 + I T ) R C V CC ( I 0 + I T ) R C V CC (2 I 0 I T ) R C V CC ( I 0 I T ) R C V CC + I T R C V X ( t ) V Y ( t )
Background image of page 11

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
(c) V X = V CC p I 1 + V X V Y R P P R C V X p 1 + R C R P P = V CC p I 1 V Y R P P R C V X = V CC ± I 1 V Y R P ² R C 1 + R C R P = V CC R P ( I 1 R P V Y ) R C R P + R C V Y = V CC p I 2 + V Y V X R P P R C V Y p 1 + R C R P P = V CC p I 2 V X R P P R C V Y = V CC ± I 2 V X R P ² R C 1 + R C R P = V CC R P ( I 2 R P V X ) R C R P + R C V X = V CC R P ± I 1 R P V CC R P ( I 2 R P V X ) R C R P + R C ² R C R P + R C = V CC R P I 1 R P R C + V CC R P R C I 2 R P R 2 C + V X R 2 C R P + R C R P + R C V X ³ 1 R 2 C ( R P + R C ) 2 ´ = V CC R P I 1 R P R C + V CC R P R C I 2 R P R 2 C R P + R C R P + R C V X ³ ( R P + R C ) 2
Background image of page 12
Image of page 13
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 05/03/2009 for the course ECSE 2050 taught by Professor Monahella during the Spring '08 term at Rensselaer Polytechnic Institute.

Page1 / 112

ch10sol - 10.3 (a) Looking into the collector of Q1 , we...

This preview shows document pages 1 - 13. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online