# Exam#03 - ECSE-2410 SIGNALS AND SYSTEMS SPRING 2009...

This preview shows pages 1–9. Sign up to view the full content.

ECSE-2410 SIGNALS AND SYSTEMS SPRING 2009 Rensselaer Polytechnic Institute EXAM #3 (110 minutes) April 15, 2009 NAME: __________________________________________ SECTION: 8:30 am 10:00 am Do all work on these sheets. One page (both sides) of handwritten crib notes allowed. Calculators allowed. Label and Scale axes on all sketches and indicate all key values Show all work for full credit Total Grade for Exam #3: Problem Points Grade 1 10 2 10 3 10 4 10 5 10 6 10 7-9 6 10-12 6 13-15 6 16-18 6 19-21 6 22-23 4 24-25 4 26 2 TOTAL 100 Exam#03 – Spring’09 – p.1

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
NOTE. You must use properties and tables. Solving problems by directly integrating the defining integrals is not acceptable. 1(10). The step response of a system with transfer function () 1 1 2 2 + + = s s H has the form . Find () ( ) 0 , cos 1 + = t t Ke t y t step θ ) radian in ( s and K . Exam#03 – Spring’09 – p.2
Exam#03 – Spring’09 – p.3 Extra page.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
- - + + () s X α + s s 2 s Y 2(10). Find such that the closed-loop poles ( i.e. , the poles of ( ) s X s Y ) have 4 3 = ζ and n ω as large as possible. Exam#03 – Spring’09 – p.4
Exam#03 – Spring’09 – p.5 Extra page.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
3(10). A signal with spectrum () t x ( ) ω X , shown below is ideally sampled at a sampling frequency of 10 = s rad/sec and then filtered with the ideal filter shown. . Exam#03 – Spring’09 – p.6 5 5 12 12 π 2 2 2 X ( ) t y 1 5 5 ( ) H ( ) t x t x s () ( ) −∞ = = k s kT t t s δ (a) Sketch the signal spectrum s X for 25 . (b) Sketch Y , the output of the filter. In each case, scale vertical axis! ( ) s X 4 2 6 8 10 12 14 16 18 20 22 24 -2 -4 26 -6 -8 -12 -14 -16 -18 -20 -22 -24 -10 ( ) Y 4 2 6 8 10 12 14 16 18 20 22 24 -2 -4 26 -6 -8 -12 -14 -16 -18 -20 -22 -24 -10
4(10). The circuit shown represents a second-order low-pass Butterworth filter with bandwidth equal to 2 rad/sec. Find . C Ω = 2 R L C x ( t ) + - + - y ( t) Exam#03 – Spring’09 – p.7

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
5(10). Find break frequencies 2 1 ,
This is the end of the preview. Sign up to access the rest of the document.

## This note was uploaded on 05/03/2009 for the course ECSE 2410 taught by Professor Wozny during the Spring '07 term at Rensselaer Polytechnic Institute.

### Page1 / 19

Exam#03 - ECSE-2410 SIGNALS AND SYSTEMS SPRING 2009...

This preview shows document pages 1 - 9. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online