Chem390_solution_10 - 2 Chem390_solution_10.nb Plot#F2#g',...

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Unformatted text preview: 2 Chem390_solution_10.nb Plot#F2#g', F3#g', F4#g', g, 0, 100' 0.025 Solution to PS10 0.020 0.015 0.010 Problem 1 0.005 (a) See below for results. 20 40 60 80 100 F#gB, DB' K g +1 g s 100/ ; D 100 Solve% 0 F#g, 2' g m 1, K) F2#gB' Solve$g F2#g' m 0, g( g 3 !, g 100! Solve$g F3#g' m 0, g( g 25, g 100, g 100 Solve$g F4#g' m 0, g( 100 K g +1 g s 100/ s. ##1'' 2 K 3 (b) Most probable grade is there F becomes maximum. 2500 !! 3 ,1 g 100 0 g 2 2500 100 Solve% 0 F#g, 3' g m 1, K) F3#gB' K g +1 g s 100/3 s. ##1'' K 1 500 !! g 20, g 100, g 100, g 100 1 500 1 g 3 100 g (c) average grade 100 100 Solve% 0 F#g, 4' g m 1, K) avg2 40 0 g F2#g' g F4#gB' K g +1 g s 100/ s. ##1'' 4 K 3 1000 !! 100 avg3 1. 33.3333 0 g F3#g' g 3 ,1 g 100 0 g 4 1000 100 avg4 1. 28.5714 0 g F4#g' g (d) root mean squared grade 100 rms2 1. 44.7214 0 g2 F2#g' g Chem390_solution_10.nb 3 4 Chem390_solution_10.nb 100 rms3 1. 0 g2 F3#g' g Problem 2 (c) Plot of I and ). Plot#Erf#z', z, 0, 5, PlotRange 0, 1' 1.0 37.7964 100 rms4 1. 0 g2 F4#g' g 32.7327 0.8 (e) standard deviation 0.6 sig2 0.4 rms2 ^ 2 avg2 ^ 2 20. 0.2 sig3 rms3 ^ 2 avg3 ^ 2 17.8174 0 1 2 3 4 5 sig4 Plot%Erf#z' S 1.0 rms4 ^ 2 avg4 ^ 2 2z z2 15.9719 , z, 0, 5, PlotRange 0, 1) (f) fraction over g=50. 0.8 100 1. 0.6 50 F2#g' g 0.3125 0.4 100 1. 50 F3#g' g 0.1875 0.2 100 1. 50 F4#g' g 0 1 2 3 4 5 0.109375 ...
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This note was uploaded on 05/04/2009 for the course CHEM 3900 taught by Professor Park during the Spring '08 term at Cornell University (Engineering School).

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Chem390_solution_10 - 2 Chem390_solution_10.nb Plot#F2#g',...

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