Chapter 16 Evens Answers

Chapter 16 Evens Answers - 2 n(H 2 O = 0.1324 mol 5.99...

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16.2 Five d -block elements can be found in Appendix 2B with positive standard potentials. They are Ag, E ° = + 0.80 V Cu, E ° = + 0.34 V Au, E ° = + 1.40 V Pt, E ° = + 1.20 V Hg, E ° = + 0.79 V 16.14 (a) FeCr 2 O 4 (s) + 4 C(s) → Fe(s) + 2 Cr(s) + 4 CO(g) (b) 2 CrO 4 2 - (aq) + 2 H 3 O + (aq) Cr 2 O 7 2 - (aq) + 3 H 2 O(l) (c) 3 MnO 2 (s) + 4 Al(s) → 3 Mn(l) + 2 Al 2 O 3 (s) 16.56 Cu(II) compounds contain one unpaired electron (3 d 9 configuration); Cu(I) compounds have no unpaired electrons (3 d 10 ). Therefore, Cu(II) compounds may be colored and paramagnetic, but Cu(I) compounds are not. 16.82 n (H 2 O) = 2.387 g H 2 O × 2 2 1 mol H O 18.016 g H O = 0.1324 mol n (Cl 2 )= 1.57 g Cl 2 × 2 2 1 mol Cl 70.90 g Cl = 0.0221 mol Cl
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Unformatted text preview: 2 n (H 2 O) = 0.1324 mol 5.99 0.0221 mol = Six water molecules are present in the complex. 16.84 Concentration (mol/L) Ni 2+ (aq) + 6 NH 3 (aq) → [Ni(NH 3 ) 6 ] 2+ (aq) Start 0.10 0.75 0.0 Assume complete rxn. New initial 0.0 0.15 0.10 Change +x +6 x-x Equilibrium x 0.15+6 x 0.10 x K = 1.0 × 10 9 = 2+ 3 6 2+ 6 3 [Ni(NH ) ] [Ni ] [NH ] = 6 6 (0.10 ) (0.10) ( )(0.15 6 ) ( )(0.15)-≈ + x x x x x = 8.8 × 10-6 M [Ni 2+ ] = 8.8 × 10-6 M [NH 3 ] = 0.15 M [Ni(NH 3 ) 6 ] 2+ = 0.10 M 16.86 The above isomers are chiral and enantiomers of each other. These isomers are not chiral....
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