ME2135_Shah_prob 1 to 6 of tut 1

ME2135_Shah_prob 1 to 6 of tut 1 - National University of...

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Unformatted text preview: National University of Singapore Bachelor of Technology TM’EHJ — Fittfd Machonics' H Tutorial Sheet 1 t [urhomaehinery u pumps] (1} A centrifugal pump impeller for pumping water has inner blade tip radius rl = [1.1 m and outer blade tip radius r: = fl. 1 T5 to. The blade widths at entry and exit are b] = b; =t}.tl|45m with corresponding blade angles [3. = 30” and 133 = 20”. For a running speed of 144C! rewmin, determine the following: (a) the flowrate through the impeller, and [b] the theoretical torque required to drit-‘e die impeller. You may asstune the design conditions of whirl—free [o] = 9ft" ) and shock—free entry to the impeller. [0,245 m3is; 5416 Nm]. (2) A centrifugal pump has an impeller with dimensions r1 = 15 cm, r3 = 15 cm, b. = 5 cm, b; = 3 cm, {it = B; = 3ft“. For a discharge of 55 litr‘see and shock-free entry to vanes, compute (a) the speed, {is} the head, {c} the torque, {d} the power, and {e} the static pressure rise across the impeller. You may neglect losses and assume whirl- free entry. [514.3 rest-"min; 3.838 m; 33.914 Nm; 2.09% kw; 21349 kPa]. [3) An axial flow pump operates at Silt} ret'i'min. The outer diameter of the impeller is fit} mm and the hub diameter is still} mm. At the mean blade radius, the inlet blade angle is 12.J and the outer blade angle is lfifl, both measured with respect to the plane of the impeller rotation. Sketch the corresponding velocity diagrams at inlet and outlet. and estimate the following: {a} the heat] generated by the pump. {b} the rate of flow through the pump. it} the shaft port-er consumed by the pump. Assume a hydraulic efficiency of Sit-E:- and an overall efficiency of toe/t. 1ir'olurnetrie efficiency may be assumed to be 1.0. [4.15 m; 1.t}12 min; sass ktt'}. {4) A given pump rotates at a speed of 1666 reyt'min at its duty paint and generates a (5) (5) head of 12.2 in when pumping water at a rate of 6.6151 mall's. Calculate the head generated buy a similar pump of twice the size operating under dynamically-similar condition and discharging 6.6453 m‘h’s. Assume the efl'ects of viscosity are negligible. Determine also the rotational speed of the larger pump. [6.86 m; 3T5 rew'min} A centrifugal pump running at 2956 reyfmln gave the fcllowing results at peak efficiency when pumping water during a laboratory test: Effective head H = T5 m of water. Florate Q = ass mite. Overall efficiency 11 = T6%. (a) calculate the specific speed of the pump in dimensionless terms based on rotational speed in rews. (h) a dynamically-similar pump is to operate at a corresponding point of its characteristics when delivering 6.45 mils of water against a total head of ll'ir m. Determine the rotational speed at which the pump should he run to meet the duty and the ratio of its impeller diameter to that of the model pump tested in the laboratory; stating any assumptions made. What will he the power consumed by the pump? [06”; HTS revimin; 2.63; 67”} kW]. The characteristics of a pump in terms of dimensionless coefficients may he approximated by CH = S — ECU — ElDCQ'. Such a pump having an impeller diameter [1.4 m and running at 24.13: ren’s operates against a system characteristics represented by H = 26 + 366' Q‘. Determine the flowrate delivered and the pumps operating head. What would he the flowrate through the system if two such pumps are connected: {at} in series: and (h) in parallel. Use miss for Q. rn for H and rein-"s for lN'. [6.2]?lulx's;34.121n;{].2551n3.r"s;{J.326 mh‘s]. DA Shah lair-"Feb 2603. hull THRE¢MfiQH¢NEEY TM 2451 xiv 2 mafia adj; Fl'mr‘afg firemij Lm¥efl~cr a, = (2771”: bl ) vm Mikel-CE. VT” : VlthLF, £1 : Zwrllb mmrg] : 2‘1?{fl-[)2ffl-D+5}x150-7Q$‘ffln3£ II C: p _p. '5'“ El.” “a. Ln Tramway; TM“ 7; (pan wlvfl) [Eh/114%). Vt, : 0 4w mUria-Frfl 3mg ; 01':qu V“: film: anmfil EL 01%; — : ._____——~___~ : 4.9mm}; mm “2' infill), arm-HSNmmS) 1 . .q a - a Vt; :[U-l15)[i5u.7515}_. 3:le : r1. Th: mfg T =loELr1Vu 103(5-24-6)ffl‘|?5)(f2.7ll)1 SH-T-ENM _ u ngffi-g : 1.3M: mfg V“. - 133$? - Rim-,1” ma"); ‘8 n [1 : r. @452 MKS 2: E *1: 1 m; “ ' Hf jwribz .11: (0-6)!!!) ‘33..) T; Vt; : {n-I£){§s-%??) ' H452 “'th : firlfléqwg = (Vim) V4.12 : $~€8E m 63 Wr TOW/M T: PEI r5-th : I03x(55?¢l5BJfo'ISNH‘TW’) = 39%» NW 53(1an 359mg 2: 2. MW kw” H Ex'L-JC _ HEnfrfl + H citrus LmM+r _" i HLL of Hg The 6} IL V Z Eil— -1- E1 : __?I + .——r-l 4;- HE,- Jpq 2g ‘3 if} LEW W AWL/t- “551% Sn: . FL 2 'SP:”F=3= Vl “‘VA .) + I? l j LE-xlmfifi-f; 1|." — V14] 1 ( flied Lia/3’ : 3- f+4$5 x E 2‘. ._ _ /_ (Ax/"11!; III/l _ kgml + Vt: : _ if}, I WTM an=vm ((3-13 We (a,va Ifw m p6 ;: 105(1'.9H5)(fi.2§7g)[(0«2%?5)(52 35.¢?)+ (Ham?) calf] (5235??) ; w:3%55 w H : PE : E—fi—hi'u’égégflfia' 1-. "uJ-isik I i E Pg?) l¢3x1.0H5x‘f~§| M WHPHMP * C W' ' ‘m ) Her - W C: with. Ella = : H£:( .9?)(!+-1?54):q.i§%m 9m W HPUMP 9% ‘9 h: “Vivi Pmr : 9&3 Hr”? 07M Pam-r QM Pig 5 P _ EQflHPHHP [QBXLGHSVQ-EIXHL-ISQI'; —' av w wfl— ,._ nmflil a“? : 59%;; kW Nu. Qua; 3 Pl: -g‘ _ __ LOT-ixgr : SEDGXZ'JI w if}: 2.30 mm 59 _ : 52-36% hJ-x‘i M rim moo ._.. .— . ___________ ._._ [ Vizvnt fil:*2a WV v‘é'r—cfi Yr, TMUU ‘ I 5:" 1 _ 557.7" H F, :1?th V1, For EhTra ; V4: V1.” = TAMI-UMP: : WM:(fl~1.§75)(52-§5fi‘q>“bim12fl : 3436:? W5 ILHVKIIWJT‘ := v?“ IT: ( Plifl r121] (in : 3.:qu Ta [(U-HSDZ—(U-Dl] : “91‘s “3/5" Prawn/D Afiruugfi M fl:’)7vQ; : I‘DIISmg/j :th V)“:le W1” PE 171.0 = v11)mm : parw(rw«VH1M/3L)Mw 4' 9.4% wt Pg? -. N"; 10:10 T‘Fm J Ht: :Lzm M Di W —Mtw N1: ‘3' E H; ?’ , 61. VLSW ' M (cg) = (ca); 81 <51). ST W ’ Mm e7 N1” 1 _ E Su-flI-J-S}, N} i (—3,) { 04151 3am- CCQ).= (cm; ) Eli. : iii; NI‘L‘DE Nib; 84: Ma : O~013anE/§ Ema I fit": 0-35 Mal/SJ H'l:j5h«1’ fl[:7ézi - ' | FL D - ‘ 5’wa M N“: MW : 1:: )msyé [(fimr'flujjifl we“ [1) m V; CE N5 ‘ M5 W Nlfll : n-mmz ( H )3“ :5 Ni: 32%;; 907%: = (“T-Eran? ) (HERE; “1&3 Mar-{+5 : 11-3759; ‘r‘ps d‘r FBTZ-S rpm (ijl:(cfi>l a; (Jay- LE : We xm DJ Nl E1: ram; 005 W E: 163% W 011an (WWI/(Ham?!) at,» M p _._ mistamcmom) MW W’t l 0““; PM“ RE ,WH’HM : Mmékw a.“ 9d; PWI‘S fiflimfihthS Wngflgs -_ CH : g—LC&~110 C: E 0‘" fllJ—r— :I <3 _ REL ___ 11:: i N’D?’ N133 flffilfib'i G) I, fr. 5 '25:: [IO/EM b ': M NI: {Vlifir- rm'jl [Ian-I 3‘: l ‘L/ "" WGJ TL; PM}? ch-qrmrtigs 2%” a'-§ih5k Pun}? L5 Hg, : 7510.3 — WW Sis — 9399-61; G3 gubgm—Lfflt ‘5’ w+er£ "f0 JIJEL M Hfi'ffilfi): HWS(®)L514H @261 I Dr _ Te-ma— 11-317 a - 936.2 a“ : Era—1.5596312 W I L MEG-1 EL + £23176! # 5.9105 :— O EM WSSQHE WT“ [Q >43) {:5- Q a o~ 1|? MW; // a» 34. 3 ,1 DLWLA _ H W” ” (subgtm%&m@) as; as 551;. 4.9 (a): 5mm ‘3" Q 1 4 Hscrizs : 2x H5 has) “(fl-{Pf 51:61:; = .2xiTé-103u warm — “92-512) : H€fo :Lo+3cm{fli h. Ian-49f _,. lumésua — Jazz-anti .90 Wang; a 1 class rug/s / ‘3“; {if}; MS 4w EqrM '. :‘thll w 1_-_"__-I TM Pump MEL dqmwri‘fl/ics a": E? a . '5 Fer————£_—=>f ‘3- ME W W L5 “Pam: H3 1 H _ rm # .1 Hrqmfi 76.203—113WKE) Egg.g(%>. ...
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This note was uploaded on 05/05/2009 for the course ME ME2135 taught by Professor Me2135 during the Spring '09 term at National University of Juridical Sciences.

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