F05prelim2s - 3 Problem 3. (20 points) COUNTER C B A ENT D...

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ENGRD 230: Introduction to Digital Logic Design Fall 2005 1 ENGRD 230 – Fall 2005 Prelim 2 Solutions Problem 1. (15 points) Method 1 Method 2 Note that Q* = J·Q’ + K’·Q = (A+Q)’·Q’ + (B+Q’)·Q = A’·Q’·Q’ + B’·Q·Q = A’·Q’ + B·Q Either solution is acceptable. NOT inst6 D Q A B CLK Z D Q A B CLK Z
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ENGRD 230: Introduction to Digital Logic Design Fall 2005 2 Problem 2. (20 points) Several solutions are possible. The simplest is this one. Alternatively, SLSI = QA’·QC’ or QA’·QB’·QC’ or QA’·QB’·QC’·QD’ + QA’·QB’·QC’·QD SLSI = QB’·QD’ or QB’·QC’·QD’ or QA’·QB’·QC’·QD’ + QA·QB’·QC’·QD’ Note that since S1, S0 is either 01 or 10, the A,B,C and D inputs are never used so connecting these inputs was optional. All other inputs had to be connected to something. SLSI SRSI B C CLK CLRN D S1 S0 A QA QB QC QD 74194 D VCC QA QB QC QD CLK
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ENGRD 230: Introduction to Digital Logic Design Fall 2005
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Unformatted text preview: 3 Problem 3. (20 points) COUNTER C B A ENT D CLRN CLK ENP LDN QA QB QC QD RCO 74163 COUNTER C B A ENT D CLRN CLK ENP LDN QA QB QC QD RCO 74163 GND VCC GND VCC CLK Q0 Q1 Q2 Q3 Q4 Q5 Q6 Q7 ENGRD 230: Introduction to Digital Logic Design Fall 2005 4 Problem 4. (20 points) A [0] B [0] D [0] C [0] E [0] F [1] G [1] 1 1 1 1 1 1 1 0 0 0 0 ENGRD 230: Introduction to Digital Logic Design Fall 2005 5 Problem 5. (25 points) (a) State diagram (b) State/output table EN A S 00 01 11 10 Y S0 S0 S0 S0 S1 00 S1 S1 S1 S0 S2 01 S2 S2 S2 S0 S3 10 S3 S3 S3 S0 S0 11 S* (c) Transition/output table EN A Q1 Q0 00 01 11 10 Y 00 00 00 00 01 00 01 01 01 00 10 01 10 10 10 00 11 10 11 11 11 00 00 11 Q1* Q0* S0 [00] S1 [01] S2 [10] S3 [11] ENA ENA ENA EN EN EN EN EN ENA ENA ENA ENGRD 230: Introduction to Digital Logic Design Fall 2005 6 (d) Draw a circuit diagram for your circuit. D Q D Q EN Y1 Y2 A CLK...
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F05prelim2s - 3 Problem 3. (20 points) COUNTER C B A ENT D...

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