Answer to Tutorial1 - R: 7057 5,9 1.3.6 = 103.13 .2514...

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Unformatted text preview: R: 7057 5,9 1.3.6 = 103.13 .2514 .11.. :: 1n 33-2 Eda—BAP 2 200:1«CIM 5 .fl: “(0 39.2 MW3J+ a 53AM)» at: B to 03 \go’hfll’ k lokoflj (3 2.0 13917 ‘14 Lb) 6: 1W5? : 6E — (:58 i ' = Quiche; + {311va + 1517+: 3 * (flamengmfiwn- E_____ mu (— VH7; man}; 6%.; mm H 393M \ Liv ‘3 #g,_.__1_§73‘ MM _ -=~ ,1 Q- 01? 32 + (35231)2 + (r M43531 _ '-"~ . I‘ . iww‘“ - (a) (“www.3ng 91 f3 fl 3% EM“ Co [Q ITli- :31),2 = (-«I 1932+ @3001 .2 5200M# - _ = (at z":+Q-’E)_-_( nut"; Mfi 1 ALE): 2.1+ V" J u‘um‘flT m = $4; = 0.336598: 444w = (2115?: “13+ - . w..- . .-._|, fl, —9 ——_¢L’B'B—:DE '— OR 4W — (‘;+;3+afi): = WWW— . ’3 [RI one was“ we [2 “u Spam cm —°/°& 2‘: {3? R 13% ' : _~_ (2“? fi)'(2.x+%‘+gfi.) Qua-J Os: 8 WHEN “elixir El alt 2.1+ I“ 1*214rg2 + 3? __ _ $ ? + S {Q 2:- :11» J 58 23.365 _ _W— U on krb‘m E?) :2 m =2t2wx 7‘ I _ pcth H L13*9'+6i3-(t£+o‘+ofz) PM“. 11+C~531+ (,1 . I . m 2 23' I 65- -— 8:1: "QM-ea -‘ v B .= (;i_g‘ +6‘E)C@l+4b‘ +012) . “*5 M‘ i — :2 RT: H rm}: go‘s) beam) = 3,: M/s a 2 :2.s~,{+.3g : 9.9;: w(s:fi:__ s... ;_—s,.:+ 16x 4% =L9m £*-1‘§Jj%/s#_ (lg/q 2 _ réggr 2 a 13mi~632Lé£+ =—_l 3;; + {$.6j ; W1551 to =QRfH: -.» QQEO a "Sig—m: I'LQ'T“ r‘see M r: 1:5 Lzzmi’s ___ __ é=3 “419%. _________ ____w ‘3‘” '2 (05142 + 031-13) 4- {.9,7,_.( .. 039cm: 4, offng ) __ ____ __o_g_q_m U913 = 0.341;: ‘— 43:“? W19 u 4:. )i’ 4‘ _ m 0.3%”: + (+913 . _ LflWw-‘itpw/ar'? ____.é__.___.“Dial. = $336+ ‘tjt‘ _..~______§____§;.S_§__MJ 5 if in E1 . _ fl H _______5k_= k1” — Miller {- L16 + 1Y9)€9 \i L» LmUDLU-ul *1) 9!“ z: o “923:3, 4713091) (3 + L raw—ex) + 2(1Lil‘ee —— - —3 filg-Bfl+9fib}_ml%‘ . ___._,__n =mswf+ = “M? “1% I . +1“ AW Bffwéw. _ -mu, 1 LE: — (was ‘m/s 17-15011: ZOLM/S a I = 2t: «M2.» er—mgo as) = - ‘02.. - t7-32Q9 0°C V313 = VB~ VA = wer - 2? 68129 CL My, mam: figr+reee __ C9 _ _ d_ “flex—oaakémgl/sfi; N r=LC 1 _ ' ‘ ‘" _ ‘““ ~LL T F}; +( QUMLW ‘QB _ LEGO-Er e“, _ _ T: {8 er W (Ls/a = QB‘ 10k ) Q9": 0 ...\.____ noo_,,___ : —'—‘ "'\ _..______._. Jaw”! LU “9.3.. 0:9 :' \‘ \ 2 u ‘ ‘ A =' — Q 21mg __/“\ ____________ __Lg,gfi1m w5.21% gag/32 r + grffig ghee LL Ln 9% “ _ .. __ __ _£ raj- 29839; O ____________,,_‘_“____iwm(393g _Q% + 2 H (to) (— 06%) o = v 2‘ =7 1 " b _ _._o a W! “’3 /5> .44; _ _C~ mg ml (S. __ 147;: (WWW so°£__4c__w(um2§(j I LL “:4 + L\—% 2 ;= (221+ 3.1Léj_3_w/s% .____. .__._m__ “.0. = V9Lg‘" V B. % (an ) )7: km“ 519; + 552353 134/34,? “ m UL: {per 4— Y‘é Q9 GB=LFiFFé2)Qr+L1Fé+ __ ,nM// a; U3 : u) e: + (0.5M?) e9 = 1 3:; + 2.5416 ere-r .__—. Q'rh _ 251. / .j.‘ /// ______ a _ /3° —¥..—_lfi_3*;T—- _ 3' u "I \fB : m H :» 0930}? (—9.5) Natty-$603; + 3/1m5b°+2.sm5§)2 ‘ ml; 0 m _____: EO-EQQK + 2.669944; ..\____©‘&__E_.M_Leim;§) (501 )QL: L 2 L‘)(g) 4” O‘rto) ) “ _"_12'9QI‘ 4: U3 QC} : C" DE 0330‘” -— liaa 52:0 )4: J. ( —— 12‘5"»; 33° + Nubia“) I 1nd! ...
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Answer to Tutorial1 - R: 7057 5,9 1.3.6 = 103.13 .2514...

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