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Unformatted text preview: Note that the product formed in this reaction is racemic the structure of only one enantiomer is written below. CH 3 H Br Br CH 3 OH (solvent) OCH 3 H CH 3 Br Br CH 3 OH 2 In the space below, propose a mechanism for the overall transformation given above. Use curved arrows to show movement of electron pairs, and draw structures of all important reaction intermediates. Show all lone pairs and nonzero formal charges! If a reaction intermediate is a resonance hybrid, it is only necessary to draw the most important contributing resonance structure. (racemic)...
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- Spring '05
- Organic chemistry