equation_sheet(1).pdf

# equation_sheet(1).pdf - e = 1.60 10−19 C k = 9.0 109...

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Unformatted text preview: e = 1.60 10−19 C k = 9.0 109 N∙m2/C2 = 1 me = 9.11 10-31 kg mp = 1.67 10-27 kg = mn c = 3.00 x 108 m/s ⃗⃗ ⋅ ⃗⃗ = cos ⃗⃗ × ⃗ ⃗ ) = − ( 0 = 4π x 10-7 N∙s2/C2 ⃗⃗ × ⃗⃗ | = | ⃗⃗ || ⃗⃗ | sin | ⃗⃗ × ⃗ ⃗ ) = − ( |1 2 | CH 21 Coulomb’s law: = ⃗ = 0 ⃗⃗ 0 = 8.85 10-12 C2/N∙m2 40 ⃗ ⃗ = electric dipole: 2 ⃗ | = sin | ⃗ × ⃗ ⃗ | = | area 2 cylinder: surface area 2 + 2 2 ⃗ ⋅ = ∫ cos ∫ ⃗ = = ∑ 1 = 2 2 , 1 = electric energy: 1 1 + 1 2 + = 1 3 2 2 4 3 0 3 work-energy theorem: = potential difference: − = point charge(s): = ) CH 24 capacitance: = |∆| series: volume 0 = − ( ) , = − ( ) , parallel-plate capacitor: = +⋯ = 0 ∑ continuous charge distribution: = ∫ E-field: = − ( ⃗ ⋅ ⃗⃗ = Gauss’s law: ∮ ⃗ volume 2 = ̂ ̂ sphere: surface area 4 2 ⃗ ⋅ = ∫( cos ) CH 23 work: = ∫ ∆ = − = − 2 ⃗ = − cos ⃗ ⋅ ⃗ =− ⃗ ⋅ ⃗⃗ = ∫( cos ) CH 22 E-flux: Φ = ∫ ⃗ circle: circumference 2 ⃗ ⃗ = ∑ ⃗⃗ = ∫ continuous charge distribution: ⃗⃗ × ⃗ ⃗ ) = − ( ⃗ = 2 ̂ point charge(s): ⃗ 2 2 = 0 = parallel: = 1 + 2 + 3 + ⋯ 1 1 2 2 = 2 = 1 = 0 2 2 0 CH 25/26 = = 1 = ∆ = ⃗ ⃗ = = 1 1 + 1 2 + 1 3 ⃗) ⃗ × ⃗ CH 27 ⃗ = ( ⃗ ⋅ ⃗⃗ = 0 Gauss's law: ∮ ⃗ σ = 1/ρ ⃗⃗ = = ∆ = 2 = = Σin = Σout junction rule: parallel: ∆ loop rule: +⋯ ∆ 2 ∆loop = ∑ ∆ = 0 series: = 1 + 2 + 3 + ⋯ ⃗ = ∫( × ⃗ ⃗) ⃗ ⋅ ⃗⃗ = ∫ cos Φ = ∫ ⃗ ⃗⃗ ⃗ = magnetic dipole: ⃗ | = sin | ⃗ | = | ⃗ × ⃗ ⃗ = − cos ⃗ ⋅ ⃗ =− ⃗ = CH 28 ⃗ ⃗ ×̂) 0 ( 4 current loop: = 2 0 2 2( 2 +2 )3/2 ⃗ ⃗ = 0 ∫ 4 (×̂) 2 long, straight wire: = ⃗ ⋅ = 0 Ampere's law (steady I): ∮ ⃗ 0 2 ...
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• Fall '08
• Staff
• Physics, Magnetic Field, Electric charge, Continuous Charge Distribution

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