Dennis To
PHYS 1410L Sect. 812
Projectile Motion
6 March 2018
Jaden R., Kevin L., Andrew R.
Objective:
-The motion of the projectile in the gravitational field will be studied
to gain an understanding of horizontal range, maximum height, time
of flight, and trajectory of the projectile.

Introduction:
At one point in our lives, we all must have seen balls being set into motion. We must
have noticed that the motions of the ball form a curved path in the air. Balls that are set into
motion mostly have a two-dimensional motion instead of one. In this experiment, the same
type of motion will be analyzed. This motion is called a projectile motion, where the motion
of the object is divided into two components(the x and y component). Two of the many
important reasons why people study projectile motion are launching cannonballs at the right
target during war and scoring goals in sports.
A launched object has an initial velocity. The horizontal and vertical component of the
velocity will be determined by using the following methods.
V
x
= V
cos
θ
V
y
= V
sin
θ
Where: V
x
= horizontal component of velocity
V = velocity
V
y
= vertical component of
velocity
θ
= angle that velocity makes with the horizontal
Through studying the projectile motion, we will be able to discover many things.
These include the time of flight of the object, the horizontal displacement, the vertical
displacement, and the equation of the trajectory. As air resistance is neglected throughout the
experiment, the object will only be accelerated by the acceleration due to gravity(g). The
horizontal and vertical displacements can be determined by using the following Kinematic
Equation.
s = ut +
1
2
a
t
2
Where: s = displacement
u = initial velocity
t = time
a = acceleration
For the horizontal motion
:
replace s with x, u with u
cos
θ
The equation for the horizontal displacement will be
x = u
cos
(
θ
)
t +
1
2
a
t
2
since air resistance is neglected and acceleration due to gravity only acts vertically, the
acceleration for horizontal motion is 0. Therefore, the equation for horizontal displacement
will be:
x = u
cos
(
θ
)
t
(let this be Equation I)

For the vertical motion
:
replace s with y, u with u
sin
θ
The equation for the vertical displacement will be
y = u
sin
(
θ
)
t +
1
2
a
t
2
since air resistance is neglected, the acceleration of the object is only the acceleration due to
gravity(g). Since y is measured upwards, the acceleration will be –g.Therefore, the equation