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**Unformatted text preview: **IIII Boost ‘5'“ 2:13 pM 4 >3 30% [EM < How did the Electrostatic Force change from Trial 1 to Tri
9 Subscribe to unlock Task 4: Post-Lab Exercise watch this video that explains the content if you need help with these problems. F = karzq 2 where kcis Coulomb’s constant, 8.99 x 109 N nf/Cz. clcctric itive and a negative charge, each with a magnitude of 1.41 x 105 C, are separated by a distance of 0.44 In. Find the for
Fthe particles. You must show your work for credit. View a Sample Problem ivens: kc= 8.99 x 10 ql and q2= (+/-)l.4l x10'5 r2= .44m
nknown: Fawn.c
quation:
F . = k“ 2 Answer: 4.062N
electric r2
lbstitute: (8.99x10"9).(l.41 x IDA-5 C).(-l.41 x lOA-S C)/.44"2 =
31%: 4.062 at distance of separation, I, must two 3.20 x 10 '9 Coulomb charges be positioned in order for the repulsive force
nem to be 83.4 N? You must show your work for credit. View a Sample Problem ivens: q1 = q2 = 3.2 * 10 '9 kc= 8.99 X 10’ felectric= 83.4N
nknown: R2
quation: Answer= .0332 m 2 km 2
electric 1-2 lbstitute: 83.4=[8.99x 10 °][3.2x 10 ' was ﬁve: r=.0332rn charges 1 and 2 have equal magnitude. The diagram above shows the electric ﬁeld lines surrounding them. Which c
ing statements is true? ~ '—-- ‘* e G a to] ...

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- Fall '15
- Force, Electric charge, TRI, Electrostatic Force change, nknown