hw3 - Overton, Mays Homework 3 Due: Jan 28 2005, 4:00 am...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Overton, Mays Homework 3 Due: Jan 28 2005, 4:00 am Inst: Turner 1 This print-out should have 13 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. The due time is Central time. 001 (part 1 of 2) 10 points The velocity v ( t ) of some particle is plotted as a function of time on the graph below. The scale on the horizontal axis is 8 s per grid square and on the vertical axis 8 m / s per grid square. 1 2 3 4 5 6 1 2 3 4 5 6 7 8 9 v ( t ) time (8 s) velocity (8m / s) Initially, at t = 0 the particle is at x = 62 m. What is the position x of the particle at time t = 32 s? Correct answer: 702 m. Explanation: Looking at the v ( t ) plot we see that over time t = 4 8 s = 32 s, the particles velocity decreases from the initial v = 4 8 m / s = 32 m / s to final v f = 1 8 m / s = 8 m / s. The v ( t ) line is straight, which indicates constant deceleration rate, hence the average velocity is given by v = v + v f 2 = 20 m / s . Consequently, the particles displacement during this time is simply x = t v = 640 m , and its final position x = x + x = 702 m . 002 (part 2 of 2) 10 points What is the particles acceleration? Correct answer:- . 75 m / s 2 . Explanation: The average acceleration of the particle is a = v t = v f- v t =- . 75 m / s 2 . Since the v ( t ) line is straight, the acceleration is constant, hence a = a =- . 75 m / s 2 . 003 (part 1 of 1) 10 points A car traveling in a straight line has a velocity of 6 . 62 m / s at some instant. After 7 . 65 s, its velocity is 12 . 4 m / s. What is its average acceleration in this time interval? Correct answer: 0 . 755556 m / s 2 . Explanation: The average acceleration is a av = v t = v f- v i t = 12 . 4 m / s- 6 . 62 m / s 7 . 65 s = 0 . 755556 m / s 2 004 (part 1 of 1) 10 points Vectors ~ A , ~ B , and ~ C are shown in the figure below. For convenience, the tails of each vector are arbitrarily located at (0,0)....
View Full Document

Page1 / 7

hw3 - Overton, Mays Homework 3 Due: Jan 28 2005, 4:00 am...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online