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Unformatted text preview: Overton, Mays Homework 13 Due: Feb 23 2005, 4:00 am Inst: Turner 1 This print-out should have 13 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. The due time is Central time. 001 (part 1 of 2) 10 points Note: The pilots apparent weight is the force that the seat exerts on his body. The acceleration of gravity is 32 ft / s 2 . The pilot of an airplane executes a constant-speed loop-the-loop maneuver in a vertical plane. The speed of the airplane is 453 mi / h, and the radius of the circle is 1847 ft. What is the pilots apparent weight at the lowest point if his true weight is 184 lb? Correct answer: 1558 . 23 lb. Explanation: Given : g = 32 ft / s 2 , W = 184 lb , and v = 453 mi / h = 453 mi 1 h 1 h 3600 s 5280 ft 1 mi = 664 . 4 ft / s . At the lowest point the apparent weight acts up and the true weight acts down, so F c = W b-W W b = W + W v 2 g r = 184 lb + (184 lb)(664 . 4 ft / s) 2 (32 ft / s 2 )(1847 ft) = 1558 . 23 lb , if the real weight is W . 002 (part 2 of 2) 10 points Note: If the force is negative, the seat-belt must be used to hold the pilot in his seat. What is his apparent weight at the highest point? Correct answer: 1190 . 23 lb. Explanation: At the highest point the apparent weight and the true weight act down, so F c = W b + W W b = F c-W = W v 2 g r-W = (184 lb)(664 . 4 ft / s) 2 (32 ft / s 2 )(1847 ft)- 184 lb = 1190 . 23 lb . If the value is negative, the pilot must be strapped in. Be careful with the units again. 003 (part 1 of 3) 10 points A person stands on a scale in an elevator....
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