Homework12Solution.pdf - Hw1| 91 I2 7[791 1 rd 0(1 1'n w 10...

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Unformatted text preview: Hw1| 91 I2 7‘? [791) 1’) ’ ’rd‘ 0(‘1 1‘" 'n w ‘10 LV‘“ en» ‘13] f“)“‘*\ d» M‘J .12 2 N ‘ n:*u:L-4 y‘- “W“ I (“‘0‘ i‘ m {R I ’ 49bié¢ VAL; wsUE Fa, . («J1 c In”! ‘I in (um)! . Lxfl! m 1“» Pun... N aloo use we CM +784 kl ““83 o‘L-J’ 641‘. U 1“ 1"“: were “,4“ .. mama musing“, 5*433‘134 C,‘ ‘t&« s, .= LL: 3» it .31 we. “I m S,c0 (‘b‘nfibw sLLvlim 3AM N‘ ,t a " “(warm ‘1 46-75%?— usNS 9‘3‘ s aRM‘tM't‘k (SAN 'Sz .. Lark m! 4k 4'03] i méumk AM RN! -.- MLN—wdqflmfi 1 L4 ‘00! 2 36052 #321. “z 3514!.- La 5‘0! a “46.60 +29?- . WM?- = 551:3qu? (iguana) . 9.31,: 0‘32 'S/k S1 + 06 m". , mu! «5 4mm" 35-5?! my” ;. 534?. its)" .2 am" I”, ' ‘ T: “mg i S. Mama“) E‘CWVS/k; f -2;sz 2. A 9B+C The change in concentration of B is NJ to obey the following retattonship, d[B]/dt = HAP”, where k is a constant and 1 time Ak ~=> 61163. .. m3” wt BM EN 3315 alt v» £53 . Jay: [93” . Derive a rate equation for this re ion In terms of the concentration of [A]. 8 d skiekow J'tb a! 31 J _ «J [“1 For the followlng reaction 5. Cosan b. You have the following data fro previous experiments monitoring the reaction in part a. [W‘- m“: 51;: - ”L =7 szM“ twal/5 4* 300s HI!“ ~ m” 2 3w men 3315 W s. Cogan 3. For a reaction of interest involving the 4onsumption of species A according to the reaction, A => products You find this is a first order reaction with te constants of 4x10" 5'1 at 25°C and 7x104 5'1 at 50°C. If this reaction oowrs at body temperature (FTC) with an initial concentration [A].=0.SM, what is the concentration after 20 minutes? ‘ ‘ Rt 25°C a: the 15* d“ J 93%; k: {I Ho 3 canal! ”s ‘1 4“ ETC? Us: "Hue AfiLfiMw Febrm‘m ‘1‘- age k 5 4} h \ .J .- “g .L __..L ‘11.: Rte 421.: W Vl (it) h K (7; T‘) e (005* In flg'c «NJ 5‘02 rank Cowb*¢u.4) (0272. k vie“ C. so 348 K owl 32.?K)1 5J4: {n E} Ea: 'q‘IQO? 3/ ] 4' u‘fims a: name] W1 L. LT‘ 55 «(it aqe k .3610. ml Se}; T; z.- ‘51:) K. aloe, £2“ “Hue \‘ofiq camifi‘od .. ll- .. L2 (HR) = 93 no 5 l men 3315 W & Cogan W A S-mer polymer having a group { energy - can exist in the following 8 confi microstates have the same energy, specifi anal-I. S glgjéigw 5 tone end capable of hydrogen bonding - and thus reducing urations with microstate energies E1 through E. Some of these ally E2=E3 and E4'E5 Ea E1=E3. i fieeflgfgl a. Write an expression for the molecular pertition function In terms of the molecular state energy levels and the gegenerag of the energy levels. your final answer. T‘Aere axe. “area 0 Es 61: 5:3 6., 9‘ s n. X I l La {5 a mlecu‘” Mo‘ewjor Pap‘i‘lua {vuokC-iAI‘sumMQol (we? Q~k°~fl$ “Quid (MN! L92“ ‘oe’cbr Y“ R” 6L figs? 5;— (wank/ma . - Fir/LT BMEN 3315 =§6:57: $6 rite out com letel :the should be no ummation si n in Vii/QC Q4033 (LN-L, w ? Ht Acaoqmeb AA: gamma, 50 “C H“ E “ lust, Ei/k‘r - Ez/U + 32 Q 5 or if - €./L’T _ 9’ rt 8 “f a e, gz/‘LT + S e 661$“! Se Page 1 of 5 S. Cogan b. Arbitrarily setting the energy of states E4, E5, E5, E7 and E3 equal to zero, by experiment we find the energy level of states E2 and E; is equal to .02 eV. By experiment we find the energy level of state E1 Is equal to -0.05 eV. What is the probabillty df finding the system in energy level £1 at a temperature of 310 K? (Boltzmann’s constant, kl, = 8.62 x 10'5 qV/K for energy in eV) E1: “ecstv Elwgnoew E @.-E‘1tdei:&:0 De‘gewhe '3: ewixl + £WW‘L4‘ - ("aw/U -(- WMgr Jen/en Ci = Q P Q, + 5 6 RT = (8 Hub“? eV/k) (3109 = o. o 26? eV 0.0%., 1} 002/, 1,26 Olk+be o.oz£?~+g is 451 + (#23 + S : l3s7‘t “ER/UT BM EN 3315 Page 2 of 5 S. Cogan ...
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