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NCEA Level 3 Physics (91523) 2016 — page 1 of 6 Assessment Schedule – 2016 Physics: Demonstrate understanding of wave systems (91523) Evidence Statement N1 N2 A3 A4 M5 M6 E7 E8 0 1a 2a 3a 4a OR 1a + 1m 2a + 1m 1a + 2m 1a + 1m + 1e 1a + 2m + 1e Q Evidence Achievement Merit Excellence ONE (a) Correct diagram and labels. (b) The first pipe produces a lower frequency, so it has a longer wavelength and a longer pipe length. The wave speed is constant. v f so a lower frequency means a longer wavelength. The wavelength of a standing wave in a pipe is proportional to the pipe length. Lower frequency pipe / 350 Hz / first pipe is longer AND one of correct description of relationship between frequency and wavelength OR Longer pipes have longer wavelengths Statement relating wavelength to pipe length. AND Statement relating wavelength to frequency to explain that the first pipe is longer. (c) The phenomenon is called beating (beats). The two pipes produce similar but different frequencies. At one time, two waves arrive in phase and add constructively (loud), a short time later two waves arrive out of phase and add destructively (quiet). Beating occurs / beats occur. AND ONE of: Links loudness to phase or type of interference Explanation linking phase and interference to loudness changing over time to produce beats
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NCEA Level 3 Physics (91523) 2016 — page 2 of 6 (d) f 1 762 Hz beat frequency 4 Hz f 2 766 Hz 3rd harmonic 766 Hz so v f 343 766 0.4478 m 3rd harmonic .... pipe length = 3 4 L 3 4 3 0.4478 4 0.336 m ALTERNATE SOLUTION f 3 762 Hz f 3 '= f 3 4 766 Hz ( f 1 f 2 f beat ) 3 f 0 766 Hz f 0 766 3 v f 0 L 4 v 4 f 0 343 3 4 766 0.336 m Correct value for 2nd pipe frequency.
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  • Fall '17
  • ZAHEER AHMED
  • Frequency, Wavelength, NCEA Level, NCEA

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