91523-ass-2016.doc

91523-ass-2016.doc - NCEA Level 3 Physics(91523 2016 page 1...

• Notes
• 6

This preview shows 1 out of 3 pages.

NCEA Level 3 Physics (91523) 2016 — page 1 of 6 Assessment Schedule – 2016 Physics: Demonstrate understanding of wave systems (91523) Evidence Statement N1 N2 A3 A4 M5 M6 E7 E8 0 1a 2a 3a 4a OR 1a + 1m 2a + 1m 1a + 2m 1a + 1m + 1e 1a + 2m + 1e Q Evidence Achievement Merit Excellence ONE (a) Correct diagram and labels. (b) The first pipe produces a lower frequency, so it has a longer wavelength and a longer pipe length. The wave speed is constant. v f so a lower frequency means a longer wavelength. The wavelength of a standing wave in a pipe is proportional to the pipe length. Lower frequency pipe / 350 Hz / first pipe is longer AND one of correct description of relationship between frequency and wavelength OR Longer pipes have longer wavelengths Statement relating wavelength to pipe length. AND Statement relating wavelength to frequency to explain that the first pipe is longer. (c) The phenomenon is called beating (beats). The two pipes produce similar but different frequencies. At one time, two waves arrive in phase and add constructively (loud), a short time later two waves arrive out of phase and add destructively (quiet). Beating occurs / beats occur. AND ONE of: Links loudness to phase or type of interference Explanation linking phase and interference to loudness changing over time to produce beats

Subscribe to view the full document.

NCEA Level 3 Physics (91523) 2016 — page 2 of 6 (d) f 1 762 Hz beat frequency 4 Hz f 2 766 Hz 3rd harmonic 766 Hz so v f 343 766 0.4478 m 3rd harmonic .... pipe length = 3 4 L 3 4 3 0.4478 4 0.336 m ALTERNATE SOLUTION f 3 762 Hz f 3 '= f 3 4 766 Hz ( f 1 f 2 f beat ) 3 f 0 766 Hz f 0 766 3 v f 0 L 4 v 4 f 0 343 3 4 766 0.336 m Correct value for 2nd pipe frequency.
You've reached the end of this preview.
• Fall '17
• ZAHEER AHMED
• Frequency, Wavelength, NCEA Level, NCEA

{[ snackBarMessage ]}

What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern