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Unformatted text preview: 6 , 70 . 833 + 1 . 96 8 . √ 6 ² = (64 . 632 , 77 . 234) . Since 80 does not fall within the conﬁdence interval, that men and women metabolize methylmercury at the same rate is not believable. 1 Problem 3. The length of the conﬁdence interval is 2 z α/ 2 σ √ n = 2(1 . 96)(14 . 3) √ n = 56 . 056 √ n . For 56 . 056 √ n ≤ 3 . 06 , n ≥ ± 56 . 056 3 . 06 ² 2 = 335 . 58 , so take n = 336. Problem 4. (a) P (1 . 64 < Z < 2 . 33) = 0 . 94, a 94% conﬁdence level. (b) P (∞ < Z < 2 . 58) = 0 . 995, a 99.5% conﬁdence level. (c) P (1 . 64 < Z < 0) = 0 . 45, a 45% conﬁdence level. 2...
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 Spring '07
 Xu,Lily
 Statistics, Normal Distribution, Maximum likelihood, Estimation theory

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