PHYS218_CHP01_51-60

PHYS218_CHP01_51-60 - 1.51: a) From Eq.(1.21), A B b) A B...

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1.51: a) From Eq.(1.21), ( 29 ( 29 ( 29 ( 29 . 00 . 14 00 . 2 00 . 3 00 . 5 00 . 4 = - + = B A b) ( 29 ( 29 [ ] ( 29 . 7 . 58 .5195 arccos 39 . 5 00 . 5 00 . 14 arccos so , cos AB = = × = = θ θ B A 1.52: For all of these pairs of vectors, the angle is found from combining Equations (1.18) and (1.21), to give the angle φ as . arccos arccos + = = AB B A B A AB y y x x B A In the intermediate calculations given here, the significant figures in the dot products and in the magnitudes of the vectors are suppressed. a) , 13 , 40 , 22 = = - = B A B A and so 165 13 40 22 arccos = - = . b) , 136 , 34 , 60 = = = B A B A 28 136 34 60 arccos = = . c) . 90 , 0 = = B A 1.53: Use of the right-hand rule to find cross products gives (a) out of the page and b) into the page. 1.54:
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This homework help was uploaded on 03/25/2008 for the course PHYS 218 taught by Professor Safonov during the Spring '06 term at Texas A&M.

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PHYS218_CHP01_51-60 - 1.51: a) From Eq.(1.21), A B b) A B...

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