This preview shows pages 1–3. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.View Full Document
Unformatted text preview: 32 Figure 1 r n 1 = 1 n 2 = 1.37 Assignment 2 Solutions Question 1 (8 Marks) 3 2 2 O 2Al 3O 4Al + O 4H + 3CO 5O + H C 2 2 2 8 3 2NH N + 3H 3 2 2 6 4 2 3 2 2 2 O S Na + 2NaI O S 2Na + I Question 2 (8 Marks) (i) Calculating the angle of refraction We can calculate the angle r using Snells law; sin sin i 1 2 n n r = Remember that the angles are always taken with respect to the normal to the surface, so the angle of incidence is; 8 5 32- 90 = = i We are given that n 1 = 1, and n 2 = 1.37, then using Snells law to calculate the refracted angle gives; sin58 1 sin 37 . 1 = r 24 . 38 1.37 58 sin arcsin = = r Therefore, the angle of refraction is 38, or (this answer cannot be accurate to more than 2 significant figures). (ii) Calculating the wavelength of the light in the liquid We know that for the light beam in vacuum; Wavelength nm 470 = Velocity m/s 10 3 8 = c And we know that the speed of light is different in different media depending on the refractive index; v c n = , or n c v = (1) where n is the absolute refractive index of the medium, v is the velocity of light in the medium. The wavelength and frequency of a wave are related to its velocity by f = v , which means that the frequency is given by f=v/ . The frequency will be the same in both media this is because the frequency represents the number of wave cycles arriving...
View Full Document
- Spring '08