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Unformatted text preview: David McEwen S0091331 1 ENTA11005 - Assignment 3 Question 1 - Young’s Slits First to find the slit separation:- Fringe separation, x = 2.82mm Screen distance, D = 2.2m = 2200mm Wavelength, λ = 590nm= 5.9 × 10-4 mm Slit separation, d = ? x D d d D x λ λ = = µm mm d d 460 46 . 82 . 2 10 9 . 5 2200 4 = = ∴ × × =- Therefore slit separation = 460µm Now the slit width can be calculated:- The diffraction angle, α must first be found using Pythagoras. The adjacent side is the screen distance of 220cm The opposite side is the distance between the central beam and the 1 st minima = 6.5cm ° = = ∴- 69 . 1 220 5 . 6 sin 220 6.5 = Sin 1 α α α Slit width, a = ? Diffraction order, p = 1 Wavelength, λ = 590nm = 0.59µm Diffraction angle, α = 1.69° µm a a a p a 20 69 . 1 59 . sin 59 . 1 69 . 1 sin sin 1 = ∴ = ∴ × = =- λ α Therefore slit width = 20µm David McEwen S0091331 2 Question 2 - Specific Heat To find what the ring is made from we need to find the specific heat capacity of the ring, c. The total weight of the full glass was 330g so to find the weight of the glass the weight of the water (225g) was taken from 330g to find the glass weight of 105g....
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This note was uploaded on 03/25/2008 for the course ENTA 11005 taught by Professor Colingreensill during the Spring '08 term at A.T. Still University.
- Spring '08