sp08_quiz_sol1

# sp08_quiz_sol1 - ECSE 2050 Introduction to Electronics...

This preview shows pages 1–10. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: ECSE 2050 Introduction to Electronics Spring 2008 Quiz 2 Print you name on every page, Show all work to ensure partial credit. Problem 1 (15 points) Problem 2 (10 points) Problem 3 (25 points) Problem 4 (20 points) Total Problem 1 (l Spts) For the PMOS ampliﬁer shown below, assume th= -0.8V, Kp’W/L=3.5mA/V2. Neglect channel length modulation 2.5V -=- *2.5V ‘3. ~"/U(i)For VG] = V02 = 0V, Find the following voltages (Vx, Vy, Va], and Mg) m i Name ; if \ —. 4,:“9‘ a, g 2‘“; 9/: f‘%“:2méi~ f3 ‘i ‘W‘f‘é : W ., / 0!; g £2 a 7M0“ (iii) If VG]:VG2:Vin, What is the maximum value of Vin after which the transistor M3 leaves its operating mode (changes from saturation to triode) ,4 / ww ,1 ,K w a A y”: g m WE m tax/w fig: :1 5 ,,- ’3: ii ; 2/2 3 \ . i; A xiii“ 953*» £4 \$1 f,g§;"‘§/<f‘\rwm 1,, ‘.\ x W: (1 1’ 3M. { ; adv ‘” CE? ‘32 “”3“ “W“ ‘ waawaésam WVQM }» ‘r mima V“ E Y “’1 ,1 f if i; x a > 3/ Ext/EC!” ‘ p 1 113‘ .11: a E ‘- ‘ 8.41:” i E13391? 2? ~ {2.4 \3 : ff; '21 A \$§z€A§km/%“Wyyw i A" \Eé?) ‘ .3. j a, g . 5M ,«3 x {If 53;" 5“; {3 _ ; av ~ r // {7/ ? 1/ §’(/‘ N f; \5//{/-, ,N M 4; ’z/ ‘3 "3 a w E 32%]; ' Dig; t g g f "‘43:“ / ”<4 i/ g: WM' ii A 5% (2‘ A {3/ A,” a L; {3 if .._/ 3 3 I, I l S 1: ifw’ W 5:13“, ﬁtting; '7“ 5 F7 ; ' is, g}?! 's ’ i ii 53? ”gig ” as g“ If: M \ If? a ’ ’ V ’ pic 3 ix; i § ii: £3 :32. A? 1: w Ami». ;’ ‘ l 2 “Q ~ . ' a t Wit: 2 E tax“. 1/3“ ii:~4xg:} \_,/" kw— , :Mxmiﬁ f I“ a 3‘ ‘ 1 / v ﬁbwﬁr :3 «v :4 ” :2}; ; n 2 w m ‘ ¢;._ I i 2 ix ; €/ V i4/ ‘x 1 M ,s yr \ 4: 3/1, 2* , v a; ,g M a: a '; q w My 2’ ”’1 f < A ‘ V 5: 3 ix ”‘2“? L i I» g 3; :3 g y w . at; 7 L f M W WW”? ‘ i. 3 K Rb ., / 2/ M g/ 5/ U) Name: Problem 2 (10pts) For the circuits shown below(parts a and b), use VTn=0.4V, K’W/L=2mA/V2. Neglect the channel length modulation Sketch Ix as a function of Vx . Assume Vx goes from 0 to VDD=1.8V. Determine the value of Vx at which the device changes its region 0f operation. E” 7?”; €53??? 5/; £5: l 5,31 Aw“ ﬁx “3 i,’ : Ix y/ m E? W P we. X ”A k} 1 q“ a”) e. ’2 w “w VVVVVVVVVVVVVVV “"6 333/ ““533“ 3:? , s ;§Amﬂwgyw§ / ML _ﬁ«, VVVVVVVVVVVVVVVVVVV _,i‘ ‘Ml / . , eg SIX SKA; 73' ‘.:~ w..__:;»~§ / 3‘7 a ”"3" [Ar 5 M W s / i g E ‘g f M" t A? 5 . 2 a? A e~i<€h , » / 2 we L * ‘3 Ex M. 3?} 5 3 M n 2 7‘ .45: kg}: If! a ‘ < ;// M g// 1'2 w 5%] X g/‘g’f u/ / 3 "‘2 x..- f: 3% m f 2 K; 5 m ‘ g’ x; m g x a A ~ 02 d ﬁgs?” 3» -A c i * l me e. : g 5 r a wee a» 5 , ‘ _." 1 ,‘V :3 7 5X31“ ; z , i A“)! ‘ g}§%/Z‘(é';ywﬁ,§’e Z 3% J l J / /“ [a / 5‘?! 1 4 \$12; \$6; / m g} ' 5‘ 2 _ {A yes < egg as} w t 1/ C” s /’ /’ § K / K: » f g M 3/; x\ I ,» 3 «> i ré ~ ﬂ l " w/ \e \ 2 \ V: "> {3 a»; :z :1 {,(/"\J \4 \ \Vx HM /: .2 K % i g “N“ """"" M: 3 ,.._. ifé/ix A?” 5 ”5 % i w» f t 9.; t :3 M if“ ’ e M,» MA»V \w A new :3 e : :21egswé’mz 951% ,3; wmwxﬁ“) 4,: s 2 , x m L“ g f 3 455 is g l s , w, i :11; W / / e we szwmmmw 4 {.5 L x / E» Name ”\ z; E / {2.41: rm “f"; a? \ x: . wk; Problem 3 (25 pts) Name: +15V 0 Rd 1k R91 C3 Vout Rsig C2 100uF ‘OOUF lngmA 10k 0 + Rload t R92 4k § Vll’l Vsig Rs C1 ' 100uF 200 0 TO Answer the following questions for the circuit shown. The transistor is an N—channel enhancement type MOSFET. Given: Vt = 1V and K’W/L = SmA/V2 Rgl and Rg2 have been picked so that ID = 8mA and Rg1//Rg2 = 80kg. For parts a) w (1), use k=0. Draw the small signal model for the midband frequencies. 1 Mnrﬁr—awmm ». ; s " l f/ « f a); W {i m gm U” M“ W ”Wm : t m \“ ‘Qytﬂr‘; ‘ Ex». M m 5&3; g g u 5; 5ng r‘ in i” M/kg‘fxa, ,«j l \ ““er ”Mn N AN {’L E: 1?” M? WNW g; E“ t 6 iv} 3, ’1‘ E {3 ’3 “ ﬂ g j A Y #2:}; 3 gig“ KEV? £5 1/; Kg); 3 g i“ r 3 7 V ‘” tag? 2 g; g f J ﬁzz“? “K i ‘3 a: l I; K E :“x a M g A ‘5 g g E 5:35 5 § W "~ 3 ”Al/ZR," \\:> 3 g 5 Lifaef «Kat/‘3‘ . 3 (w i ‘gké (é Ry? Name 1% Vout/Vs Vent/Vin and Gv= d) AV, and Gv, where Av Problem 2 (continue mine gm, {1) Deter X h? f 3 f a? ,3 13 e 9 w. M I)// n W w. i: ﬁx», , L? as x 5m ,. g??? is i xi» “XW a; 3). 5 {M x my,» («my a; w d n a .m S 1V5 a n a y c n e u q e W... h 3%,: K m x. : f V 5.; #C 2x 6 £3 7 ,: 1/ y t ,: u JV: .m OK / :M jg? m. C x Q: g m 5 : ﬂ ,1 A a m” infuiwd : My a ,K, Q43 8 f... i w ma 4” . : X: m m ﬂwwgiu Vni if... ﬂy 1 0 c: t m D. M 2 3/ Xx: .wb w g : l 3 8:: ﬁg 1 . . a m Wu 3 WK? MW gigs: S n 3 e i e u m W a .6. w :7 r & ..: : 9: w M m 4 an :, 2/5 m g (x. AW :5 75”.} r “.m w WW. “I, 3 Fa z; ,, Q, 5? g , a E p m 7Q. 5 « : aka a. t .1: Q ,2. 3 Ma .5 5m 15 3:: « w c . 2 r z m h : 2 3 a W .m i: ,L FD. rim sawing ; m ”Kim f! 3r: 5 e f K g : d d: .m : t gﬂhwsde % / . . : ‘ . f: . jﬁiﬂm: L :3; 7M: A ,M V V Problem 4 (25 pts): Name: In the circuit above, the NFET transistors have Vt=0.6V, V A=20. All transistors are operating with VGS=0.8V. The drain current of Q1 Id(Q1)=10,uA, the drain current of Q2, 1d(Q2)=ImA, R1=80KQ and R2=l 18m. 5 g g i, 3/: ,1? Draw the small signal model for the ampliﬁer shown below (without feedback) that is formed by Q1 and Q3, éV/ié/ ﬁnd gmla ngs I.ola and r02 5; 52’ “I: W” ””” :7: WWW“ 2’: :3 31’?!th 52; i f 5‘ {at/5 “e ie A 2; Q a 5 {g 3“ :1: km“ :7; MW" “Q :3, 4/: i: §< 4/3“ :5: 5; 5 we, 2. Find the voltage gain A of that ampliﬁer (VD/Vin). For simplicity ignore r02 while estimating the gain. { A x” r: “g if f v; 5,: 3 5‘ {l 555? :2. l’ 33 33 l a 5., // {if 5 5 e 3 «3 5 / 5‘3? 2 " 3’ €535? 7 “13‘ 5 3» w- —-a I, 3/ gm ‘" V 5 5 5" 5,4 / 54/3; 3’ g ‘39; :5 , ,//‘t 5/ 3 a...#w_ ,,,,,,,,, “4,. i 5:}? f“ 5 :2 5w - 5; .5}? ‘3 ifﬁﬁ; ‘j J: £593“ Jig/3““; 2. 5» 5 , 13/5 E/xj 5 5: a f 3 it 5‘ 552: c I" 3/ ”M” M if; V \ e": 5 // i/ﬁ M W (1/; 3/}? f 35/ :J 5 - 5/ § :3 1M 5; f? E: 9/ 5 5 5? 'V ’ l x” ,5 / / if! : gfﬁzggé ‘5 :x/ E3. Knowing the gain A, and using Miller theorem, ﬁna/ the input resistance Rz'n ’“\ 5 ”d 233, 5 a“ 3/ ,3 Wm“ , 1 A. 5 5/ 5e 4 M V 2w. v f 5 I / 5 g 5 i n ﬁx g f”: / W v S ’v 5-3;> 5 ,,,,, /’ g \7/ 3 1/ g 5 i 7 m I z ,/ f E , < / 3 5) 35 53 5, / 5! ;{{:J E x / 5 i. éxgy/Lﬁ M 1 l f 3/3 555‘? if C: M ’ 5x 5/ 5?? W N .5 :2: a» / / 3 ~ g/a» ix" 5 K j; v :25? a 55/5 5 355}; 5.2 w 5?», i «w r“ 5/ X i 5 5<255~5~yi§3 \ ) 5 ’ w {:3} 3 5:515 5i 1. gig: ’ t / l /' ,w W {J -H ,, 5 ,5 3, gig/é {<5 M 5 ~~ {513353; 15/ lO ...
View Full Document

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern