HW7 - PROBLEM c7-20 EACH STEEL WIS/"6514 [Ms/4...

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Unformatted text preview: PROBLEM c7-20 EACH STEEL WIS/"6514 [Ms/4 (£059 SEc71oA/AL Ammo;qu mm? E = zoo 6P4, 2m 30W 70 PM”: USE THE /‘1£7//aD 0F wen/M WORK AW 95 m?ng 77/5 HAW/41 olspmcmsA/r or POI/UT A 50LU710N: I) mum/VS 5,” 1.5.. a P é__ w No 17:, caM/wztw [En/fuse 5p 25 ,4 1,4an MAW; Axm. F0205 own rig/Mag 1'" ((2/1an Wsz)+Zo(/&)+’3b(3)ro => flx=~éok C I 'FN=6°(W TIM/V 51 301,47 EQUZLZBPYVM Am, Fgfiéawér $287an —Zo~3o=o a (r Sou/7‘ 1,290 : so -c,=o =7 (x: gar/«lea N zokN 30* 2) £69er Bum/17C , q F“ 'rl‘zrfo: gaugozo w FEc=—éz.5k~ oie lag/MIC), 4.3 .4—éokA/ + _ 3 ,, ' " F“ T azFx‘o. — 60134425)— F3< so =7 F“ =4sz on 11.51?” c) 501w ‘ 3) 562011.132: um AT 8 _ ‘ *TZF5=01 F56“20=O =>Fss= 20"” (T) F” TFQE N 1 _ ‘ h __ F ' ' 5 ,5 617.51: aia-ofwaqm-o .2 m~775w 0L 775W (0 H)£Qvu1321um n E ‘ 5 “final” +fZ Fy=0i g-(42.5)-20—%F35 =0 :7 5;:325 kN (r) CHECK$2H=0IéO—§(é2.§)-§(325)= 0 ,'_0K F é2.§w ‘5 20m 5) 5/45 mam Faliogs PRC»ng 3— 10 (02szst QAFPL)’ men/AL (IA/27' FOELE AT ,4 [.5m l-SM av; lvin=05 ' ~ 7) gauuraenm AT C “if Pa 3 LSIUV .4...— 4.— Fu 1"”! wEQUZLIRIUH AT E ,mm +Tza=ot 30.26% m =0 e? Bangle” (2‘) FA: 0|) Mgnme mum. FozcE answa) o.7sr~(c)l KAI IKN to)\/Z€71/AL WORK gal/Arrow ‘ MEMBER (Ik/wAA: now) NM) Lm ‘ nA/L (mm) —.75 42.5 /5 29313 1.15 57. 5 2,5 M 7, 138 —.75 —22.5 LS 25.38 o '20 2 0 , [1.25 12.5 2.5 ms. 513 1.5 go 1.5 :35 z= HaIZS 21/3; 2 W125 {11/75: (1%. > ’45 ' £100 (100) MM 19"?” 433: 6.73mm‘1/ EB 15 A 25x0 {out #948er EV lflstcn0M)/M0 T/Ius F“, = F,“ 2m QZNoc= Oi 1(3) 47, (2)20 v7 D,=l.5kA’—> 42:73:05 (3-) = 0 =7 (3: NWT 1.5-0 :0 => (x= LEM! e— THE’V Fen: =L5 [MI CT) l+gFEC:O § F64=‘,125k~ 0‘ $2530; ~fic—LS + 1250;): o 2? F34=:75)w 02 0.75:» (c) CHEW-525:0? /.5—%O.25) 13-025): 0 ,',OK» ‘ 1.2m; OM ___ .004 23 MW my I PRoBLE/"I 7- 752. SAME Ag 7'20 44/19 (,gm [Sm EL!!!" USE I’HE riff/Ion 0F V1?me Wk AM gym/m: 77/5 men/u pzspMaMEA/r 0F Pom 3 Sowno”: I) AMY VIRTUAL awn macs 47 3 1,5», [,5m FY “WE 6710”; x45 44/045 M57 3g 2960 r0255 7",, ME/M’Eé; — 7i/EA/ B C fly5f 564 2520 FOAYE flffilfp Ago Tag/v Fee: [m (T) [MW 5 = 0X (If/124:0: I(I.S)- Dxéz) 3‘ fix:o.75k/v——> 3?.75/4/(7) imam: ny-a :0 a a =. 751N4— #TZF5=0: —] +4! =0 2:? :/ [IN T 2) EQUlLlE/Qlum AT E .fi ézrxi‘o :.E"‘§3"EE :0 g Eta—7, \L CHECK’fTififioi 1,2563%] :0 0K 10) VZIZTML wag}: ECQUIZZON fizz/H565 nan) ' A/(kAl) L0,) n/VL (kn/2m) AB 0 42.5 /.5 0 M 0 57,5 2,5 0 3c 0 —22.5 1.5 ' 0 BE 1 20 z 70 CE —/,29 —42.5 2.5 ' 145.3)3 DE 0.75 60 /,5 US v r v z= 302.85 , (I k”) 'A3= Zn_/_V_l; = 302.88 wzm ( l 6% )(ItJoozmmz [mamm)33,_7qufim ’15 (400M200) Mm‘ép. I0“""/,..1L m1 IM A B = mmi NOBLE/‘4 +33 Asgmg THE flgMazks ME sz (am/E67513 Ar MEIR EM Pol/75, 4515 tour/11V 7‘ 5005 c. To Fill/D: T/IE floelzo/U‘ML PEFLECTJON ATC SOLUTIUM I)REA£710NS soot). GffieA:O; yam- )5oo(2)— éocae)=o =7 53:27am? 4 irs=o; 45+ Z7ooro :7 1592700» on woo IN, inafx:0f €004 ISOG‘JX 'Ex ’0 4x = Z/DO'EV OE ls AM Axmz am am IVE/"36R so 57 Eyuuzgzzmxtrs: +72 13:0:27oo-r 7% F” =0 => F05:- 3015.715 5; 3015.7/b (c) inEx $2560: 50/3.7:‘;'p*g=0 :7 94356154” T .1 kg 77,15” Ax = 12/00 —,/35o= 750 It «6-— k—E—fif 2) EQUILIBRIUM AT A WWW éinw: Ema—now a mama) 15(7) ~‘ mirror Ian/$1 +m~27oo =0 gm = [20011: Cr) 750 lb . Z700)!» ‘ J 3y HIS/5571043 THE/V {56:5, = [we/5(7) 4N0 69:2506lba) ’3) EQULLLBPZW"! ATC r m» 425:0: 600+ FL» /4-1 =0 «=9 Fm =-/3‘fl.élb a! mull, a) CHE(K mam: Bil/414? — Izoo= 0 $45K Fm L PfloB 9'39 (cow/Mum) 5) Mm mew; W/IT mm; AT c m Q <)"2’/7¢M=0551(8)--l(/é)= o r? F5: ZILT 425:0: Z-A3=0 =9 AyezH' l7ZF¥=O: I‘Ax‘Ex=O BY Ix/Mgcnolv Panto Mo 50 50:0 ANflT/IUS Ax=o g, 1 .1; THEN FM": Fgc =13: Z lb (7’) 4450) Fcn‘fioe A; A sea max/1423;?ngle M T5, +TZI§=0 : Z +4739 Fae =0 é Fag:— 2.23411, 0/? 2.23; I}: (c) I: 8’ 419m liyfifizo.‘ 2.23104?) - / = o .'.0/< 7) Vine/AL woflk Eat/4710A! \ NENBZR 7 0 O!» NO» L (4) n/W- (/52 H) A B 2 I200 37 Mwo M 0 Mai 2m 0 ‘ 3 C 2 Izo o 3 11200 1 5D 0 4500 “l 0 (D ' -2.23é 434/.6 3-79 Z4 533 3 05 1.234 — 30/57 8.79 6057:] 125997 i (HAMc = Z mag: [25,607 leaf; )2; ) = /,507x/p‘ Ital-i}. 4-6 \ 735‘ A. , i Ac= £507 aelo‘ -‘ __, , A; NW“? TM I‘m/15635 Me PIA/ (ad/Mcréfl Ar mm? 5w Pol/VT}. HAS/435195 43 ,m ac gxPEpzsfitE A Tf/lflfflzflfiflé? Lac/25455 0F m: 200‘)? A: z ,hl 1:: 21000 la} a 2 10“/»;: AN” FPON 1'3 ‘1 8' 3| 7o FUD: pgrsmws m: #021 am an pandas/imi- OF .001qu $0LU710A/ : 0»sz VZP7M4L water scan/A710” ("odc = in QATL = 2(2 (10“)(200)(3)) =,Oé'1’/b-# Jam/f; = .7é8’ )b'l'n Ac=.7631b~9 PRoBLEM - ASSUME 2745 (4.915635 Am; p1” cow/54750 4! 77/511? f” p01 W '5 . NEW“ ‘0 1’5 FMEIMYED 0. Sm 700 ~5fl0K’T. 8! AW FeoM‘Ivs‘i ELM" 0C— TERMINE «Tl/E you 20mm nan/Acids” or: pay/r: SoLunoN: lM/I’LY «linen/u WUIEK gauAna/V (I lb) Ac = 2 mm. = —2_234(_0,5)= /.IZ lbw Ac: fl) ‘—’> ...
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This homework help was uploaded on 03/26/2008 for the course CE 332 taught by Professor Rouse during the Spring '08 term at Iowa State.

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HW7 - PROBLEM c7-20 EACH STEEL WIS/&amp;quot;6514 [Ms/4...

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