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Unformatted text preview: Monday. February 14, 2000 JPEG image 621x839 pixels V Page: ‘ PZZI/SZOOO/Problem 1A The ﬁgure in tin: right represents part
of the. performance data far :1 mar
belonging to an ISU engineering
student. Consider the car’s meﬁnn £0
be amug the :2: axis. fine in seconds (a) (2 points) Caiculatc fram the pint the total distance traveled by the car frmn
t=ﬂs to £2505. distance. 2 52m :2 fféﬂ mﬁﬂlﬁ s} + (60m )(20 a) + ;_.{ {E30 EEISEEEE} s)
= 300 m + 1200 m —é— 600 m = ELCIO 11122.1 km. (1}) {3 points) Draw a graph 0! the. .1»; car’ 5 acceleration cemponem + q, I !
Ear) as a fugction BY time *2 In: E Eiw} WEE
far the same time intewai. lncfude numbers slang the 5; . . . ‘1
g; axm. ”if I  j a} E} 10 20 3C} 40 50 {5}
(“1351) a»; a + 6 ms far 1‘ w I"! Lu W " .Ehun I31 For
EU 5 EC: 30 5 Eiatm — 3 Ems; Eur 3851:1533 (c) (3 paints) Write an cqmtinn for Mt) far each phase or the mating. Ha tfromBEolﬂs: T'fl—(amﬂ: EE
t {mm £0 £0 3%) s: .::{th< — 300 m + (613 mi. 3EE£ — ED SE
El‘rmn 3!} m 50 5: mt} 2: {SUI} m  E at) misﬁt EU 5‘) f LS E‘IL‘Q‘SEWKZ‘  3v?) 3}“ {d} {2 points) What was the average velocity of the car during this time intervai
(It: Us to #:58 3}? ~ m: I 2213:} mi 2. .7
I’m ‘ “3;“ : ”WArMm z {43 max): 25} :x‘ hnpzllwww.pubIICJastate.edul~phy5cs’221laxams/500x145‘ij Monday, February 14, 2000 JPEG image 639x859 pixels Page: é\ P22 l/Slﬂﬂﬂfl’roblem 1.3 A hind“. {If mass m. = 313 kg starts fmm
FEST at; the top at’ a 9 == 45" indiﬁﬁ and
“£116 dawn the: incline: at distance 6f 2.9
m in L0 swarm. Frictiaen is mm: mm.
{Use g m [U Nerkg) {a} {3 paintﬁ} Draw the Freehunk fume diagram; {hr the mam (b) {3 gmmts) ﬁelemﬁrze the magnitude 0f the mzceiemiimi 9f the htnck. (fhmsc {he I 21:23:: dawn the plum: and {we 3,! mix m ﬁlm wiper left, i‘het
acceieratim: is 33ng 3h: gmsitive 1r ﬁirectiun, 30% ii has a gjtmiit'we gumpuneni ax, Sims the:
121943: sgiida‘s 3}} :11 dawn in £0 3. stafﬁng {mm E331. tibia Rafae: of 3;: can be Emmi frum ,» .\ “'1. . . “1
333‘ gt 36.3,}? at I!) m z: is ,{Eﬁ 24)" $0 :33: x a5 (3 Trust“ M {'4 WEB“) Hing NEWWH'S 3691:1196 hm Dr William tiagtwrtziue the magnitude whine
frictiume ﬁsrw muting cm the mack.
In this: 2: dirtzi‘zixzjm Newton's 5mm law giwgs
my sin I? m f = max
w 1' mm sift 1‘?  'zg‘jt'w (3 3 kg){'( it} gum}; 4 9 m4}
63.n kgm a} nag:63 » an N (if) {3 bonus madam) {htrn‘nine the: ca’ret‘ﬁciem ul'fsinetic fritfiixgn beiwietn [he hiﬁﬁk
and {he inclined plane, (We 1:: “ 113 [“5323 ~ fr: — MN 3:} m;  fgfrW’
We: know fr but we 3:550 ﬁeﬁ‘d m knaw N: The rmgnimda fa; ﬁi’Eiiw nmmai Rum: csm Eat: {Emmi 12w Apgsiymf; Nﬁwmm 50(5in
12m in Lin: {J diimximt ‘
j; #15; 6:35 t? D an N ‘ my ms if? us: {3 I?! kgﬁlf‘; NERggmié if? N Then ,m = fgﬁ‘f‘; = w mm m x 3;? a: abmt u 4.2. http://wwwpublic.iaslale‘eduIphysics_221[exams/500x1<25.ij Monday, February 14, 2000 JFEG vmage 675x805 pixels Page:
P221 /SZOOO/Probfem 1C A bucket ufwater is swung, at the end ofa rope, in a vertical circle of radius R.
The water has mass m and the mass 0f the bucket plus water is M“. (a) (3 points) Draw the freebody farce diagram for the water {III ' when it is at the
{egg of its swing and determine algebraii: expressions far tha magnitudes ofth'e
Aexmmnl forces acting cm the wafer. ﬁssumiag the bucket has speed *ut at the top 3?
its swing. L The. farce an the water are the downward
E gravitaiimalytbme m5 and the downward L normai force 3“? exerted by the: bucket on the
ﬁg waiter. {b} ('2 points} Determine an aigehrait: expression far the minimum value of vt'if the
water is not w fa]! an: aim»: buckct when the buckct is :n: the tap Grits swiw. Ifthr: water is 11m to faﬂ GUT of the bucket, mg must bala‘sg {mall7111135}? so that a
nonzero normal force is necassary (N —§— mg m mrvffﬂ). my s“: TIRE”R means that 1:: 2:» 3/ 5353 (c) (3 paints} Draw the fro€2—1:H:5{i}r farce diagram for the water {miv when it is at the «
150th (if its swing and determine algebmic expressimxs far (in: magnitudes of (he
exiemai farms; acting at: the water, assuming the bucket has speed 2% at, the. hattmn
» of its swing. ‘ '
The gravitatimai FarCE: mg is
l 1 dmwwaré and has; the magnitude 1115}, where
1 m. is thf: mass. ofthr: water. ”Flu: nm‘mal
E . farce A} is upward. Newten‘s sec0nd, law N L appﬁed m Lhe verticzﬂ direcrécm givesg: _ ,, r
mg B2 — my 2 rut'5; R 50 ‘ N mg + mvﬁR : mig + {PEER,1 http://www.public.iastate.edul—physics_221laxams/500x135.jpg Monday. February 14, 2000 JPEG image 644x447 ptxels Page: Probfem 1C wantinmm’ . . x (d) (2 points) if the maximum farce the rope can sustain withuu: breaking is 15:31“,
what is the maximum spew the bucket (:0qu 11mm? w 911; T, We must now consider the bucket and the waist as one system oftotal mass M .
The upward tensile force T exerted by the ropamusa be large enaugh £0 cmmteram the
gravitatimaal Forest: an the bucket and water and also provide that centn'pet'ai accélcration
3?szng . Thus the magnituda‘ofthe hensiun is T ; Mg :~ :k‘a'vﬁfﬁ .4: Mﬂg +9533)
T 5;. Em; means. that 19*! (g + v23??? ‘52 mec 4,
v Ax?" Eh —iJi—" ' 3w 9.4.“
so u. a \/ C M 5') http://www.publiciaslate.edul~physics_221laxams/500x14s.ipg Monday, February 14, 2000 JPEG image 668x901 pixels Page: A‘ﬂT‘LT‘fPLECHOICE QUESTIONS i. Which mm M the fnflowing ﬁsts contains may vectars. with rm scalar maintain3‘3 (A) Force. ac:celm*:1tina;mass, disgslacement
*{B} velocity, dispmcement. farce, acceleration
(C) veiucity‘ time. accelerating. force. ({1} vekmity. displacement, acceiemﬁan. mass
{E} accetemtinn. farce. avcragc speed. velacity 2. If the magnitude at" a force has the farm 157/3: when: r is the. distance: frcrm the
arigin. what are the pmper SI units far 1:? {M lxigfs‘3 £8) kg « mﬁsz *(C) kg  trig/52 [9} kg (E) kg  mfs. 3* If the pﬂsitiim vecmr {if an. abject is (2.9 In. 3.9 m, 2.9 In), how far awaf {mm
the crigin is it? ’
Mm 4.: m (B) 51) 11} ((7)51; m {m 6.3 m {13:} 6.3 m 4. Whicﬁ 0m: 01" the renewing statements is fake?
{A} If an abject? is m: ram? at a}! trims:5? its acceieratinn is aiways zem‘ {8“} if an abject is ihmwrt Emrimntaﬁy anti 2m MiaMimi abjec: drnpgm frem the
3mm; height at the same time.) they reach, ﬂare gm‘uni] at this wait: time. {C} The mas5 of an ahjact :ﬁaes mat depend on its. iacatian. *{B} The matitm a? an object is always iii EEK: directing 3f the mt farce acting in!
it. ‘ {E} Frittiamd farms are due {a eiectmmagnetic interactimm :3. 'I‘wo Masks 23f masses m :1“de are pushed alang a harizomm frictionless surface by :1 hurimnraﬁ farm P. as sfmvm in the diagram balmy, ‘Whnt i5 {he
magnimcie (if the Farm: that either :3? these blade; exrrfs m: the {:thrr? .PmmqmlMg <9“ P {3) 71:? {<7} ”if mm ﬁfgg (ng “LEW 6. W hick uf the 1131“}stng physiml quantities}; wauld nut be. constant" for an (whim!
mcwing in uniform circuiar zumiun‘.’ Agsume Hm: the Might (If {he mmnlinnm
system is :3! the tiemar ﬁfth: circle. {A} its SpCC‘d *fB} its aneelemtion {C} is distante frame the origin http://www.publicJasIata.adul~physics_221lexams/300x153‘jpg Monday, February 14, 2000 JPEG image 657x797 pixels Page: 7. A lmrizmltal forge 13 pushes a. biock af mass m 211mg}: mugh horizontal surface
at a constant speed. The freeobody farce diagram for the black Esshnwn below, to
the right; Which (if the fullawing must be true? ' *(A) P: f and N a: mg (3) P 2 f and N :> mg 2}!“
{C} P :> f and N<mg PMMVEI' 3:»
{D} 19>}: {“10 N:'mg , Wig (E) None Bf the gum» 8. When :1 car maksas ;: sharp left turn, a passenger in the car slides towards the
right side of the car. Whisk of the following explanatiens is canect? (A) Thﬂ frictional farce (m the passenger pushes the passanger tn the right. (33) The fricﬁmml Force (111 the passenger mums {in} passangcr to 339w dawn, leaving
the passenger behind. ' *{C} There is not emugh frictional force. on the passenger for the passenger to
remain at a cansmnt rad m1 distance from the center of cun‘amre of the mating. (D) The Burma} farce 0f the seat back pushes the passenger to the right. (E) Nam: ﬂflht abzwe. 9* Supgﬂse that whiéal (hit disiance between mg; elﬁctriccharges is d, the magnitude
0f the dectrit force on each of them is F. If the distance between them is reduced to
df‘l (half the. original distance}, the: magnitude 0f the eiectric form will hnmme (A) FM (131 Fry. _ {C} F (0) BF *(E) 4F m“ in an electric ﬁeld E 2 (6‘0 X 4‘06 WC)? ihe ﬂegtric farce on :m electmn will
be approximately  (A) {1139?}? {'8} (10pm {(1') {wupm’i‘
(1”) “(1095)? *(E) ——(1pN)T ' (_p m 11113) i http://www,public.iastate,edu/~physics_221/exams/sOOx1~65ij ...
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