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exam1_2007su_sol - fleafiuflt‘efl shown herein refers...

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Unformatted text preview: fleafiuflt‘efl shown herein refers to the am {we problems: A thyr eheet and its mutants have a combined weight of 180 N. a child moves it at constant speed aareea the finer ofa Ifl-m lung hallway by pulling with a tension of lflfi N on an attached rope that makes an angle of 3D“ with the horizontal. L Detennjne the_'enet'fieient afkinetie Erietien hemeen the. cheat and the. Hear. TUD¥D __ T501” '1: CIEDNBWED 3 ' 0. 6:?“ tt 1 - .1 . I“ N mfi—Tfiinah {Rwimmaflbu 2. What is the work dune by the tension on the cheat? a. D h. 321‘.) I set} .1 (:1 em. 1 e. 1000 J III-II-IH-I l-III-IIII-I III-Eli...- III-III...- a. Him A c, at: 3.54.; {mi-13,4 G. 2XE=J§XJ§ £3 #: .4 ...;_ d. Exfi=fixfi 31: E1_'E,..E (+5" “ml A C] e. E-fi=fl 1—1 4. At 1 ={L a 3.0-g_paflicle is a! the origin and has a velocity v, = will! mr’s . The malemfiun 40me partial: is £1.03 = [3.1] 1111’s3 )I , when: I is the time in mantis. What. is the position uftha particle: at I = 4.1} 5? ’c. 59:33 “2“} = KEG) +— J axffiltr c. x=Efim :1. =12!) _ _‘ g, i=13u: ' 4.0 -+ EBDH't dl" _ _ EEJJ - '-{--.D 4— 1 1: xm= HUN-j our = 0+ (4mm if U = -4.04=+'1.0t1' Alum =|+mm \ 5. A head of mass m is threaded on a wire in the shape of a vertical circle ofredius R. The bead is placed at the highest point of the oireie and given a very tiny push so that it slides [loam {see figure}. What is the work by gnvityas the head moves from the top to'the bottom of the eirele? bead «~2ng -ng 15. A rotating fen completes 12611 revolutions every minute. 1'IJII'haI: is the magnitude of the acceleration of the tip of the blade, at a radius of l]. 1 5D in? a. l:- s. RUINS: e. I56 111st a. 2er me? e. meson ma2 '1. a.“ s Rm”?- «.—. (ntfiom\( 1:61:31) 1M ran.) Tic-(341 infirm Les 1250 who ire-u 60L: 3 £26 all?“ '3". A particle. moves at constant Speed along the trajectory shown holow. Which oftho following host dmfibes the direction and magnitudc of the aooelemlion of the particle at points A and B“? a. on. = Ho = fl . a}: '5‘ h. aA=aB¢n,humpainflng south 5" W’mfi ”7’ W a. a... v: on, both pointing south ( (1;.- __ d- HA 2 an if {L “A pointing south. a: pointing north, [2. .None of the above. 3. Snow is falling vmioally at a constant spood of 311' mfs. At what 11:13]»: from the Vortioal do'the snowflakes appear to be falling as tripped by the driver of a car traveling-on a snm'ght, lovol road with a speed of SE kmih? :1 33 9* A $3 :3: {if ‘P finm’mé (E'Dmh\ o. 81' Uflhr, too-t5 (gob/k) Inga”: “'1 The situation shat-w: More refers re the next Ma pmhfems: A skier starts fi'om rest-at the top hf a ramp (point A}, slides down and jumps eff at the end of the ramp [point El}, landing in the plain at the bet-mm [SEE figure}. The end uf'the ramp is at a height efafl m above the plain. 1When the skier leaves the ramp, he is meving at fit! this aim: angle of EU“ above the horizontal. Negleet frietien amt air I‘fliistanee. 9. How high it aheve the plain is the top ufthe ramp? at. h=4fin1 b. h=62m .h=85m “r: U3 e. h=9€im t “2.. rnflln +- C‘) : W3»: 4- £016"; '1 l“) :: in! «4-- ii 2.55 1 “:3flm @0511) - i‘ "’EDm-i— . n, :kQEm I -." 1 I. A I .fl-kg blank is held a] test an a'n it'teline with angle 2t)” with the herizentefl. The coefficients ef fiietien between the bleek and the ineline are .335 = [Lit] and p. = {1.30. What is the aeeeleratlen ef the block after it is releaeed'? e. 1,2311% 13.3.4133? e. 3.3m? knitwear? (5.55.39: (1. 0&3}qu 1T]%te'£t}%€.‘+ (\J {15,15,533 IUEN f5n13m10=%61\1 )E‘mN @‘tl'éemmtmm,fcx-o 12. Two blacks with masses 2.13! kg and 43:} kg are 3333333 0 a. horizontal, fi'ietienless surface. A herizentel fete-3 F= 12 N is appfled en the tap blue}: {see figure] and bath blacks are eheerved to Move together. What is the magnitude ef the fiietien foree between the two blocks? a. 2.0M 1). ”MIN .3314 e. Emmet say because the eeefl'ieients of Erietien are net given. #535 M ”“11 IrmfieortM-tanc 9am (30-135 133::th en 35».er f“: (Ct-Okay)“ Meabfih‘t “Mflmfimm‘bfiw 11M1(6.0h5)fl, :35 2.0 ml,“- ”Ttng {11;(L30L93)(1.0;) _, I305} 13. A head of mass m at the end of'e me551e55, ideal ening of-length I movee in hmizontel oiretee at constant 5peed 55 shown below (conical pendulum). What i5 the direction of the net force on the head? 5. Veetor fit {along the string) Vector 5 {toward the center fifth: eirele} e. Vfifltflr C {toward the center of the circle and down] d. Vector D [onward floor the center of the circle] e. None of the above. GE ’tLt. coda, m er form. (mt-i? W“— Ln «In: W dirttflt'mq due Jl'b WWW kemé taut}. ...
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