{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

che210exam202

# che210exam202 - ChE 210 Fall 2002 Name Section B Exam 2...

This preview shows pages 1–6. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: ChE 210 Fall 2002 Name: Section B Exam 2 SHOW YOUR WORK! Good luck! 1. (15 points) Real Gas. A certain gas has a molecular weight of 30.0, a critical temperature of 3 10 K, and a critical pressure of 4.5 MPa. Calculate the density in kg/m3 of this gas at 465 K and 9.0 MPa if the gas obeys the law of corresponding states. W230 TL: 3\0K T: 469K PC: 4.5”MPA— P: qDMPK m Tr: .11; —. L3” = 1.6‘ 7 we“ '0 " {*‘a 2:0.94 29m Pr; 2. 1 = 3-0 J 3P6 Fe 4.5” 59*5 “I... P: MN P = 30“ 9.0MPA K 'o‘d’“ 2.91- 0.8 km! 465K "3008209m334hhgyol3uﬂ6‘ f coin/2'31 1;“ u 00; EN u x q» calquaQ. 1?“. ChE 210 Fall 2002 Name: Section B Exam 2 2. (25 points) (Combustion Reactions — Material Balances). The product gas from a solid fuel combustion reaction has the following dry-basis molar composition: ' 72 % C02 2.57% CO 0.0592% 802 25.4% 02 Pure oxygen is fed to the furnace in 20% excess (of that required to burn the fuel completely). There is no oxygen in the fuel. Assume no solid or liquid products. Use a basis of 100 mol dry gas. (a). (3 points) Draw a ﬂow chart. (b). (22 points). Calculate the elemental composition (mole% of the various elements) of the fuel. Note: This problem gave me three equations and three unknowns to solve when I did it. The most important part is to come up with the correct balances and equations. Solve completely if you have the time (solving for remaining 3 unknowns and giving elemental composition worth 5 points). Wading} 3,5“, we maul-s. D/j‘éds W7 e... ‘i‘ 6;“ “1.2 mt ) Wwa LN”? PM «6 5 n; C ",r' 2, m 0‘ «E, COL n5 5 ii 3.57 mob; CD “14 H 20% excess DZ 0'05“); mo“. 502 Who”?a no). 1 nw W\01‘1f2 3") ’3 3055mm? ac : 73‘ + =' WIS 39*5 6 eaahm : 0 beis 393/13 3 Bunkmowng “MW nH = znwi ' * ~7 “H‘ ‘8” . -* n " ‘ "T iiiiiiiiiiiiii m -7 7 01: M44. ‘ i 1 4- . 5 ’ MO)! 39501 0 he. 4- n5 1' : nu, 0 2 , / hw: 446 a; not = lilzhmear 0.25 n”) = no K TOW WW 3‘,“ 0 Gala mm: X 9110; I 3(7)? + 2.57 + (0.059234 sf 5.4) + nw'l nc+ns+nu . . WW. . ,. : 3.53.4 Mg garage“: 28.51900 0 7H 70 H 0.0234,? ChE 210 Fall 2002 Name: Section B Exam 2 3. (30 points) Air conditioner. (Gas-Liquid systems) An air conditioner is designed to keep a room cool at 19 °C and 50% relative humidity. It draws air from the outside, where the temperature is 35 °C and relative humidity is 90%. The capacity of the air conditioner is 15,000 L/h. What is the rate of water condensation? Assume atmospheric pressure at the inlet and outlet. 15,000 L/h T=19° C T235 0C ht=50% h,=90% P=1atm P=1 atm Condensed water F0, wa-[af‘c FYUW 1“b\€ [3-3 p"( 350c3= 42,176 mm”? 19" F1(‘q°cb = mm Mug 1|” tin g inlet: hr: ot‘i = PHzO ' Puzo‘ = 37.01bwmu1, 14°“ «ms 4 Maﬁa) 3er WW1 = Pd; z 31% = 0.049% ‘1’; 150 apt-5 \éDA‘l = oflSotL 19+ obi-i" . VJ.~ Ood’ie‘i’ ; My: 05: PHIB »t Fufc : 8,2355W‘MH3. 1‘04. 3 ‘PB P‘Ni‘ﬁc) 3.9-: @102 : PH°I‘;*_ 3,2385= 0,0108 ’ ‘T; ' 71:0 31"“ 5A.: = oaeqz 19* . nu W1. = = 505,434 «pi; i}; h 0.052% Lv arm 305K hm: seaee‘lz 1W “W1 = 20.0140 11°47 otdlel- 0:;A z Sum—n7. ’0 “7': “DA/3890'?” 1.0+ nwz : igniplﬂr n1 ~f nW'L: 'évlwn— . nm 5 6"593 an W bpnﬂv ‘3‘ n?) : “Wl _ nwz- I =- : W's K. ChE 210 Fall 2002 Name: 1 Section B Exam 2 4. (30 points) (Multiple Reactions: Extent Balances) Chlorobenzene is produced by bubbling chlorine gas through liquid benzene in the presence of a catalyst. In undesired side reaction, the product is further chlorinated to dichlorobenzene and in a third reaction the dichlorobenzene is chlorinated to trichlorobenzene: C6H6 + C12 9 C6H5C1+ HCl extent of rxn: £1 C6H5C1 + C12 9 C6H4C12 + HCl extent of rxn: £2 undesired C6H4C12 + C12 9 C6H3Cl3 + HCl extent of rxn: £3 undesired The liquid output from the reactor has the molar composition: 65% C6H6 , 32% C6H5C1 , 0.025% C6H4C12 , and 0.005 % C6H3C13 . The gaseous output contains only HCl. Assume a basis of 100 mol of product gas. The feed to the reactor contains liquid benzene and chlorine gas. The process is speciﬁed. (a). (3 points) Draw a ﬂowchart. Keep liquid and gas streams separate. (b). (18 points) Calculate the extents of rxn l, rxn 2 and rxn 3: £1 , £2 and £3 (c). (3 points) Calculate feed ﬂows and liquid product ﬂow. ' an we rs : an (d). (3 points) Calculate the fractional yiaﬁ of benzene. (e). (3 points) Calculate the fractional yield of monochlorobenzene from benzene La) C LL lDOmolS ﬂ (0 ; HQ” > Product 60x3 1L ———__§ 8 c\;[ L\. “up pmdud' Y“; 7 n5 3 n3 (3‘31 n5 C6 HS~Cl too more (av W5 \s “0* W 0.025m3 chqul ekSlQS‘i' basis -FJ\/ Solunj Frvbwm, 0.005’ n C u m \$0.,‘ f3‘0CCC’xQ basis +0 5 b 3 3 Stream:%. Wk Scale {lam/5 .thlawtcl. Dicky: dues ~01 all-v an; 1g» (d): 531] National ®and 42'” l’ '5' Foe, \oo mu LC . 97.03 33.07 3) .07 (‘5‘ S\ § \ £2 3 1 ,, Ht : 32.05511 n1 = 33.068” 1 W°¢ 5mm 3 302,519 at "‘3 Loo ZCLFAM NW 100 g 4,,5 8 *5 201.19 P w W 50“]? 0‘07?» 0.9le ‘Mﬁ g OJ??? as (Marsh 3 E E 5: W =5 £ 1‘ FVM‘M buzene. 2 Q7.03“6\$‘: 0L33’ 3.65 Q7433 m" = 27502.55 ‘- am. \l-n—u—I—u 3’ O\ 303\$). LC) ﬁddz MMMM be.on ; 5a; 332g “QM! 5‘2 3 ﬂ‘ - 49'qu (AS ((MLﬁAS Veranda-«4T 33‘07 MW *9 FMZQ3 0L» ~0+ :' 1°C « Decw. ; 1 10° : An C5 \$00,342, chug-C! n; 11:04 1 \33\o‘7 Pro-46: W :9» L’Ast :L :00 18 mmmw m 1:45.12, mg ma“; Lemma“? 3+3ch u; prawm sWM: W. Sidd mane £60m : 3—); : 0‘33 ken?!“ (ASSM'Kj 5.1.7.03 2 lea—«7.4.4. VJW‘O 1.9. [mm-.3 data—we) = [OD . 0333) 303.57: '2: ...
View Full Document

{[ snackBarMessage ]}

### Page1 / 6

che210exam202 - ChE 210 Fall 2002 Name Section B Exam 2...

This preview shows document pages 1 - 6. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online