sp07exam1soln

# sp07exam1soln - Phys 222 Spring 2007 Exam 1 Wed 14 Feb...

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Phys 222 Spring 2007 Exam 1, Wed 14 Feb, 8-9:30pm Closed Book, Calculators allowed Turn off all cell-phones, beepers, pagers, iPods, MP3s. . Any call will result in the end of your exam Each question is worth one point, answer all questions Fill in your Last Name, Middle initial, First Name Your ID is the middle 9 digits on your ISU card. Please fill in your recitation section in special codes K to L For the H1 section please use section 18 At end of exam, please put exam writeup back in the folder, this allows you the chance to appeal the grading Best of luck, Craig Ogilvie

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1. A block of aluminum has a hole drilled in it. When the temperature of the block is 0.00 ˚ C, the diameter of the hole is 5.000 cm. After the block has been heated to a temperature of 50.00 ˚ C, the diameter of the hole is now ____ cm. (The coefficient of linear expansion of aluminum is 2.4 x 10 -5 / ˚ C) a. 5.012 b. 4.988 c. 5.000 d. 4.994 e. 5.006 The diameter of the hole increases as every aspect of block increases. cm T D D 006 . 0 50 * 10 * 4 . 2 * 00 . 5 5 = = Δ = Δ α 2. A 0.250 kg chunk of ice at 0.00 ˚ C and 0.750 kg of liquid water at 100.00 ˚ C are placed into thermal contact inside a thermally insulated calorimeter. After thermal equilibrium is reached, the temperature inside the calorimeter is ____ ˚ C. (The heat of fusion of water is 334 kJ/kg and the specific heat capacity of liquid water is 4.190 kJ/kg) a. 25 b. 95 c. 35 d. 65 e. 55 Heat is transferred into the ice to melt it then increase the melted H20’s temperature. Heat is transferred from the 0.75 Kg of water C c m c m L m c m T L m c m c m c m T T c m T c m L m water water water ice ice water water ice water water water water water ice water water water ice ice 0 55 190 . 4 * 75 . 0 190 . 4 * 25 . 0 334 * 25 . 0 100 * 190 . 4 * 75 . 0 ) ( 100 100 ) ( ) 100 ( ) 0 ( = + = + = = + = +
3. You have some rubber and the same mass of copper. Rubber has three times the specific heat capacity as copper. You transfer the same heat energy to the copper as you do to the rubber. How do the temperature changes compare? a. ΔΤ rubber = ΔΤ copper b. Δ T rubber = 2* Δ T copper c. Δ T rubber = ½ Δ T copper d. Δ T rubber = 1/3* Δ T copper e. Δ T rubber = 3* Δ T copper Since Q transfer and mass are the same rubber rubber rubber copper rubber copper copper rubber rubber T T c c T T mc T mc Q Δ = Δ = Δ Δ = Δ = 3 1 4. You have two containers of equal volume. One is full of helium gas. The other holds an equal mass of nitrogen gas. Both gases have the same pressure. How does the temperature of the helium compare to the temperature of the nitrogen?

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sp07exam1soln - Phys 222 Spring 2007 Exam 1 Wed 14 Feb...

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