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An experiment consists of tossing two, 12-sided dice (the numbers 1– 12 are printed on the sides of each die). Let EventA= both dice show an even number. Let EventB= both dice show a number more than eight. FindP(A|B). Question options: EventsAandBare independent. IfP(A) = 0.3 andP(B) = 0.5, findP(AANDB). Question options: DB) = 0.20 DB) = 0.85 DB) = 0.15 DB) = 0.8
An experiment consists of tossing two, 12-sided dice (the numbers 1– 12 are printed on the sides of each die). Let EventA= both dice show an even number. Let EventB= both dice show a number more than eight.
EventsAandBare:
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The table shows a random sample of musicians and how they learned to play their instruments. GenderSelf-TaughtStudied inSchoolPrivate Instruction Total Female12382272 Male19241558 Total316237130 FindP(musician is a female OR is self-taught). Question options: an is a female OR is self-taught) = 103/130 an is a female OR is self-taught) = 31/130 an is a female OR is self-taught) = 12/31
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Unformatted text preview:an is a female OR is self-taught) = 12/130 An archer hits the center of the target (the bullseye) 70 percent of the time. However, she is a streak shooter, and if she hits the center on one shot, her probability of hitting it on the shot immediately following is 0.85. Written in probability notation: P ( A ) = P ( B ) = P (hitting the center on one shot) = 0.70 P ( B | A ) = P (hitting the center on a second shot, given that she hit it on the first) = 0.85 Calculate the probability that she will hit the center of the target on two consecutive shots. Question options: B ) = 0.595 ) = 0.15 ) = 0.85 ) = 1.55 On any given day, approximately 37.5% of the cars parked in the De Anza parking garage are parked crookedly. We randomly survey 22 cars. We are interested in the number of cars that are parked crookedly. For every 22 cars, how many would you expect to be parked crookedly, on average? Question options: A) 11 B) 8.25 C) 18 D) 7.5 12 / 30 12 / 30