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Unformatted text preview: Problem 2: The thermal conductivity of a material is to be determined by ensuring one-dimensional heat conduction, and by measuring temperatures when steady operating conditions are reached. Assumptions 1 Steady operating conditions exist since the temperature readings do not change with time. 2 Heat losses through the lateral surfaces of the apparatus are negligible since those surfaces are well-insulated, and thus the entire heat generated by the heater is conducted through the samples. 3 The apparatus possesses thermal symmetry. Analysis For each sample we have C 8 74 82 m 01 . m) 1 . m)( 1 . ( W 5 . 12 2 / 25 2 T A Q Then the thermal conductivity of the material becomes C W/m. 0.781 ) C 8 )( m 01 . ( m) W)(0.005 5 . 12 ( 2 T A L Q k L T kA Q Q Window 20 C -8 C Q Q L L A...
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This note was uploaded on 03/27/2008 for the course ME 364 taught by Professor Rothamer during the Spring '08 term at Wisconsin.
- Spring '08
- Heat Transfer