A
line
in
RZ
is
given
by
a
point
on
the
line
and
a
direction
point
slope
form
Likewise
in
1123
we
need
a
point
Po
Yo
yo
Zo
on
a
line
L
and
a
direction of
L
In
1123
the
direction
of
a
line
is
conveniently
by
a
vector
that
is
parallel
to
L
Let
T
be
a
vector
parallel
to
L
Let
PIX
Y
H
be
an
arbitrary point
ou
L
Let
rT
and
T
be
the position
vectors
of
Po
ie p
Denote
them
Tpo
and
OT
I
is
the
vector
with
representation
pTp
Then
F
root
I

But
since
a
and
J
are
parallel
then
there
is
a
scalar
t
s
t
a
tv
thus
I
This
is
the
vector
equation
of
L
Each
value
of
the
parameter
t
gives
the
position
vector
f
of
a
point
on
L
As
t
varies
we
trace
the
line
L
by
the
tip
of
T
J
L
a
b
c
Recall
that
it
gives
the
direction
to
Cta
tb to
F
L
X
Y
Z
to
L
Yo
Yo
707
Then
our
vector
eq
1h
F
root
tv
becomes
4h47
L
Xo
Yo
Zo
t
Lta
tb
to
LX
Y
z
Liotta
Yo
ttb
2
otto
Look
at
the
components
They
are
the
parametric
equations
of
the
line
L
through
Po
Ho
yo
fo

and
parallel
to
T
La
b
c
Each
value
off
gives
a
point
44471
on
our
line
Parametric
eq
us
for
a
line
through
Ko
Yo
Za
and
parallel
to
La
b
c
are
x
Xotaty
yotbtz
zot
find
a
vector
edu
and
parametric
egths
for
the
line

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- Fall '16
- terry bridge
- Physics, Vector Space, Trigraph, Ko Yo Za, Po Yo yo