# 280wk13_x4 - Syntax of First-Order Logic We have: constant...

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Unformatted text preview: Syntax of First-Order Logic We have: constant symbols : Alice , Bob variables: x, y, z, . . . predicate symbols of each arity: P , Q , R , . . . A unary predicate symbol takes one argument: P ( Alice ), Q ( z ) A binary predicate symbol takes two arguments: Loves(Bob,Alice) , Taller(Alice,Bob) . An atomic expression is a predicate symbol together with the appropriate number of arguments. Atomic expressions act like primitive propositions in propositional logic we can apply , , to them we can also quantify the variables that appear in them Typical formula: x y ( P ( x, y ) zQ ( x, z )) 1 Semantics of First-Order Logic Assume we have some domain D . The domain could be finite: { 1 , 2 , 3 , 4 , 5 } the people in this room The domain could be infinite N , R , . . . A statement like xP ( x ) means that P ( d ) is true for each d in the domain. If the domain is N , then xP ( x ) is equivalent to P (0) P (1) P (2) . . . Similarly, xP ( x ) means that P ( d ) is true for some d in the domain. If the domain is N , then xP ( x ) is equivalent to P (0) P (1) P (2) . . . Is x ( x 2 = 2) true? Yes if the domain is R ; no if the domain is N . How about x y (( x < y ) z ( x < z < y ))? 2 First-Order Logic: Formal Semantics How do we decide if a first-order formula is true? Need: a domain D (what are you quantifying over) an interpretation I that interprets the constants and predicate symbols: for each constant symbol c , I ( c ) D * Which domain element is Alice? for each unary predicate P , I ( P ) is a predicate on domain D * formally, I ( P )( d ) { true,false } for each d D * Is Alice Tall? How about Bob? for each binary predicate Q , I ( Q ) is a predicate on D D : * formally, I ( Q )( d 1 , d 2 ) { true,false } for each d 1 , d 2 D * Is Alice taller than Bob? a valuation V associating with each variable x an el- ement V ( x ) D . To figure out if P ( x ) is true, you need to know what x is. 3 Now we can define whether a formula A is true, given a domain D , an interpretation I , and a valuation V , writ- ten ( I, D, V ) | = A Read this from right to left, like Hebrew: A is true at ( | =) ( I, D, V ) The definition is by induction: ( I, D, V ) | = P ( x ) if I ( P )( V ( x )) = true ( I, D, V ) | = P ( c ) if I ( P )( I ( c ))) = true ( I, D, V ) | = xA if ( I, D, V ) | = A for all valuations V that agree with V except possibly on x V ( y ) = V ( y ) for all y 6 = x V ( x ) can be arbitrary ( I, D, V ) | = xA if ( I, D, V ) | = A for some valuation V that agrees with V except possibly on x ....
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## This note was uploaded on 05/21/2009 for the course CS 2800 taught by Professor Selman during the Spring '07 term at Cornell University (Engineering School).

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280wk13_x4 - Syntax of First-Order Logic We have: constant...

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