Chemistry 201X: Quiz #9 November 30, 2007 Name:_____KEY_________________________INFORMATION: ∆E°= 0redE(reduction) −0redE(oxidation) ∆G°= −nF∆E°∆E= ∆E°−(0.0592/n) log Q F = 96,500 coul/mol ∆G°= −RTln KR= 8.314 J/mol⋅K(2) (10 points)A galvanic cell utilizes the following reaction: 2 Fe3+(aq) + H2(g) ⎯→2 Fe2+(aq) + 2 H+(aq) 2 H+(aq) + 2e−⎯→H2(g) 0redE= 0.00 V Fe3+(aq)+ e−⎯→Fe2+(aq) 0redE= +0.771 V (a)(2 pts) What is the standard emf (in V) for this reaction? ∆E°= 0redE(Fe3+→Fe2+) −0redE(H+(aq) ←H2) = (+0.771 V) −(0.00 V) = +0.771 V (b) (2 pts) What is the standard free energy (in kJ) of this reaction at 298 K? ∆G°= −(2 mol)(96,500 coul/mol)(+0.771 V) =
This is the end of the preview. Sign up
access the rest of the document.
This homework help was uploaded on 03/27/2008 for the course CHEM 201 taught by Professor Miller during the Fall '07 term at Iowa State.