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(3) 1-D Motion - Lecture 3 1D motion ACT Cross product...

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Lecture 3 1D motion
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ACT: Cross product Vectors A, B and C are on the planeof the screen. They are drawn to scale. Comparethemagnitude of thesetwo cross products: A. | A × B | > | A × C | B. | A × B | = | A × C | C. | A × B | < | A × C | A B C Bsin θ Bcos θ And they both point out of the screen. θ | A × B | = AB sin θ = AC = | A × C | The cross product selects the part of B that is perpendicular to the direction of A .
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An overview of Mechanics Mechanics: study of the motion of objects. 1. Kinematics : How do things move? 2. Dynamics : Why do things move? 4. Some special cases: Rigid body motion Simple harmonic motion •Gravitational forces, Hooke’s law… 3. Conservation laws : Work-energy Momentum (linear and angular) For someproblems, themath is easier to handlewith
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The Simplest Case: 1D Motion along a Straight Line Position: A single+ or – number (coordinate) describes thelocation of an object relativeto a referencepoint (origin ). Description of motion : position x as a function of time t : An equation x(t) A graph A table of data Time (t) Position (x) t A x A t B x B t E x E t D x D , t C x C
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