Part 1 of 25 - Default:
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Question 1 of 25
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Identify the slope and the y-intercept of the equation:
y = - 4x + 5
A. slope = 5; y-intercept is (0, -4)
B. slope = - 4; y-intercept is (5, 0)
C. slope = - 4; y-intercept is (0, 5)
Feedback: Correct! The slope-intercept equation of a line (y - mx + b) is an easy way to the identify the
slope and y-intercept.

D. slope = 5; y-intercept is (-4, 0)
E. None of these.
Part 2 of 25 - Default:
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Question 2 of 25
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Choose the location of the point (- 5, 0)

D. Quadrant IV
E. Negative y-axis
F. Positive y-axis
G. Negative x-axis
Feedback: Correct! If a point is on the negative x-axis, the first coordinate is negative and the second
coordinate is zero.
H. Positive x-axis
Part 3 of 25 - Default:
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Question 3 of 25
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In which quadrant does the point (2, - 5) lie?

Part 4 of 25 -
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Question 4 of 25
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The equation of a line is 3x - 4y = 12. The intercepts should be written as ordered pairs - in parentheses
and with a comma between the coordinates.
It's x-intercept is: 4

It's y-intercept is -3
(0,-3)
Part 5 of 25 -
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Question 5 of 25
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The equation of a line is x = - 6. Its intercepts are:
A. x-intercept: (- 6, 0) y-intercept: (0, - 6)
B. x-intercept: (- 6, 0) y-intercept: There is no y-intercept
C. x-intercept: (- 6, 0) y-intercept: (0, 0)
D. x-intercept: There is no x-intercept. y-intercept: (0, - 6)

Part 6 of 25 -
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Question 6 of 25
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The point A is located on the x-axis, 6 units to the left of the y-axis. What are the coordinates of point A?