This document consists of
24
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IB10 06_9702_13/RP
© UCLES 2010
[Turn over
*6578157725*
UNIVERSITY OF CAMBRIDGE INTERNATIONAL EXAMINATIONS
General Certificate of Education
Advanced Subsidiary Level and Advanced Level
PHYSICS
9702/13
Paper 1
Multiple Choice
May/June 2010
1 hour
Additional Materials:
Multiple Choice Answer Sheet
Soft clean eraser
Soft pencil (type B or HB is recommended)
READ THESE INSTRUCTIONS FIRST
Write in soft pencil.
Do not use staples, paper clips, highlighters, glue or correction fluid.
Write your name, Centre number and candidate number on the Answer Sheet in the spaces provided
unless this has been done for you.
There are
forty
questions on this paper. Answer
all
questions. For each question there are four possible
answers
A
,
B
,
C
and
D
.
Choose the
one
you consider correct and record your choice in
soft pencil
on the separate Answer Sheet.
Read the instructions on the Answer Sheet very carefully.
Each correct answer will score one mark. A mark will not be deducted for a wrong answer.
Any working should be done in this booklet.
PMT

2
© UCLES 2010
9702/13/M/J/10
Data
speed of light in free space,
c
= 3.00
×
10
8
m
s
1
permeability of free space,
μ
0
= 4
π
×
10
7
H
m
1
permittivity of free space,
ε
0
= 8.85
×
10
12
F
m
1
elementary charge,
e
= 1.60
×
10
19
C
the Planck constant,
h
= 6.63
×
10
34
J
s
unified atomic mass constant,
u
= 1.66
×
10
27
kg
rest mass of electron,
m
e
= 9.11
×
10
31
kg
rest mass of proton,
m
p
= 1.67
×
10
27
kg
molar gas constant,
R
= 8.31
J
K
1
mol
1
the Avogadro constant,
N
A
= 6.02
×
10
23
mol
1
the Boltzmann constant,
k
= 1.38
×
10
23
J
K
1
gravitational constant,
G
= 6.67
×
10
11
N
m
2
kg
2
acceleration of free fall,
g
= 9.81
m
s
2
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3
© UCLES 2010
9702/13/M/J/10
[Turn over
Formulae
uniformly accelerated motion,
s
=
ut
+
2
2
1
at
v
2
=
u
2
+ 2
as
work done on/by a gas,
W
=
p
∆
V
gravitational potential,
φ
= –
r
Gm
hydrostatic pressure,
p
=
ρ
gh
pressure of an ideal gas,
p
=
V
Nm
3
1
<
c
2
>
simple harmonic motion,
a
= –
ω
2
x
velocity of particle in s.h.m.,
v
=
v
0
cos
ω
t
v
=
±
ω
2
2
0
x
x
electric potential,
V
=
r
Q
0
4
ε
π
capacitors in series,
1
/
C
= 1
/
C
1
+ 1
/
C
2
+ . . .
capacitors in parallel,
C
=
C
1
+
C
2
+ . . .
energy of charged capacitor,
W
=
QV
2
1
resistors in series,
R
=
R
1
+
R
2
+ . . .
resistors in parallel,
1
/
R
= 1
/
R
1
+ 1
/
R
2
+ . . .
alternating current/voltage,
x
=
x
0
sin
ω
t
radioactive decay,
x
=
x
0
exp(–
λ
t
)
decay constant,
λ
=
2
1
0.693
t
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4
© UCLES 2010
9702/13/M/J/10
1
The product of pressure and volume has the same S
I
base units as
A
energy.
B
force.
C
area
force
.
D
length
force
.
2
A vector quantity
V
is resolved into two perpendicular components
X
and
Y
. The angle between
V
and component
X
is
θ
.
θ
Y
X
V
The angle between component
X
and the vector
V
is increased from 0
°
to 90
°
.
How do the magnitudes of
X
and
Y
change as the angle
θ
is increased in this way?
X
Y
A
increase
increase
B
increase
decrease
C
decrease
increase
D
decrease
decrease
Space for working
PMT