Unformatted text preview: Third Dictionary: 1 1
z =3l-3xs _Ex6 x1 =13+—;-x5 —%x6 (xpxpxpxuxyxs) = (13,5,5,9,0,0)
basic variables x1 , x2 , x3 , x4
nonbasic variables 3:5,):6 This is the ﬁnal dictionary —- note the signs of the coefﬁcients of the x’s in the z expression (we can’t
increase 2 by increasing either x5 or x6). Optimal value of z is 31. This is attained (only) at (x1,x2) = (13,5). ...
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- Spring '03