Yassine_Angela_hw1.pdf - Problem 1 f When = 1 42 2(2(3 is evaluated at x = 2 we get-inf as the result due to the fact that the denominator ends up

# Yassine_Angela_hw1.pdf - Problem 1 f When = 1 42 2(2(3 is...

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Problem 1: f- When 𝑦 = 1+4𝑥−2𝑥 2 (𝑥−2)(𝑥−3) is evaluated at x = 2, we get -inf as the result due to the fact that the denominator ends up resulting in a zero with a negative sign that carries over from the 2-3.

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Problem 2: Problem 2-d
Problem 3-a&b

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Problem 3-c Problem 3-d,e Problem 3-f
Problem 3-g The difference in the plotted data between 3f and 3c is the amount of points. The interval of data in 3c is larger since it increments by 0.1, whereas the data in 3f increments by 0.5 for the same interval of [0 8].

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