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Unformatted text preview: 2 c I ( t ) Z s Z 1 2 s 1 rd 2 dr dz + 2 c I ( t ) Z s Z 1 2 s 1 rd 2 dr dz = 4 c I ( t ) Z s dz Z 1 2 s 1 rd 2 dr ( t ) = 4 s c I ( t ) ln 1 2 ( sd ) ln d s ( t ) = 4 s c I et ln ds d Using the magnetic ux through the loop we can nd the EMF on the loop. V ( t ) =d dt = 4 s c I 1 et ln ds d 1 Now to nd the total charge that will ow through any point in the loop we simply integrate the current in the loop over all time. Q = Z I loop dt = 1 R Z V ( t ) dt =1 R 4 s c I ln ds d Z 1 et dt Q = 4 s Rc I ln ds d (b.) To nd the work done on the loop we do the following. W tot = Z I 2 ( t ) R dt = Z 1 R V 2 ( t ) dt 2...
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 Spring '06
 reynolds

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