This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: 2 c I ( t ) Z s Z 1 2 s 1 rd 2 dr dz + 2 c I ( t ) Z s Z 1 2 s 1 rd 2 dr dz = 4 c I ( t ) Z s dz Z 1 2 s 1 rd 2 dr Φ( t ) = 4 s c I ( t ) ± ln ± 1 2 ( sd ) ²ln ±d s ²² Φ( t ) = 4 s c I et τ ln ± ds d ² Using the magnetic ﬂux through the loop we can ﬁnd the EMF on the loop. V ( t ) =d Φ dt = 4 s c I ± 1 τ ² et τ ln ± ds d ² 1 Now to ﬁnd the total charge that will ﬂow through any point in the loop we simply integrate the current in the loop over all time. Q = Z ∞ I loop dt = 1 R Z ∞ V ( t ) dt =1 R 4 s c I ln ± ds d ²Z ∞1 τ et τ dt Q = 4 s Rc I ln ± ds d ² (b.) To ﬁnd the work done on the loop we do the following. W tot = Z ∞ I 2 ( t ) R dt = Z ∞ 1 R V 2 ( t ) dt 2...
View
Full Document
 Spring '06
 reynolds
 Magnetism, Magnetic Field, Wire, dr dz

Click to edit the document details