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Unformatted text preview: P112 Spring 2007 Homework #2 Solutions Note: Solutions to boxed problems are given in detail, “unboxed” problem solutions will just contain a short answer. 1.( unboxed) Speed at the first point is 5.00 m/s, acceleration is 1.43 m/s 2 2.( unboxed) Deceleration 7.11 m/s 2 , stopping time is 3.75 s. 3. (unboxed) (a)  r A  = A = A x 2 + A y 2 = (4.00) 2 + (3.00) 2 = 5.00 . 39 . 5 . 29 ) 00 . 2 ( ) 00 . 5 (   2 2 2 2 = = ! + = + = = y x B B B B r . (b) j i j i B A ˆ )) 00 . 2 ( 00 . 3 ( ˆ ) 00 . 5 00 . 4 ( ˆ ) ( ˆ ) ( ! ! + ! = ! + ! = ! y y x x B A B A r r . j i B A ˆ 00 . 5 ˆ 00 . 1 + ! = ! r r . (c) 10 . 5 . 26 ) 00 . 5 ( ) 00 . 1 (   2 2 = = + ! = ! B A r r . ° ! = " # $ % & ’ ! = " " # $ % % & ’ ! ! = ! ! ! 7 . 78 00 . 1 00 . 5 tan ) ( ) ( tan 1 1 x x y y B A B A B A r r ( . Since ) ( < ! x x B A and ) ( > ! y y B A , the vector j i B A ˆ 00 . 5 ˆ 00 . 1 + ! = !...
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This note was uploaded on 03/27/2008 for the course PHYS 1112 taught by Professor Leclair,a during the Spring '07 term at Cornell University (Engineering School).
 Spring '07
 LECLAIR,A
 mechanics, Acceleration, Work

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