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Unformatted text preview: Time Derivative of a Rotating Vector A(t)
d dt A(t) (t) d A(t) rotates at angular speed . dt |A(t)| = A = constant, so the tip of A(t) traces out a circle of radius A. In short time dt, A rotates thru small angle d , and A(t + dt) = A(t) + dA : As d |dA| and dA 0: |A| d ( in radians), A , so . . . dA = |A| d ^ , and ^ ^ A A(t + dt) dA
d A(t) d dA ^ = |A| dt dt ...
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This note was uploaded on 03/27/2008 for the course PHYS 1112 taught by Professor Leclair,a during the Spring '07 term at Cornell University (Engineering School).
- Spring '07