HW_8_sol

# HW_8_sol - HW 8 solutions P112 S07 1 Take east to be the...

This preview shows pages 1–2. Sign up to view the full content.

HW 8 solutions P112 S07 1) Take east to be the x -direction and north to be the y -direction (again, these choices are arbitrary). The components of the common velocity after the collision are v x = (1400 kg) ( " 35.0 km h) (4200 kg) = " 11.67 km h v y = (2800 kg) ( " 50.0 km h ) (4200 kg) = " 33.33 km h. The velocity has magnitude ( " 11.67 km h) 2 + ( " 33.33 km h) 2 = 35.3 km h and is at a direction arctan " 33.33 " 11.67 ( ) = 70.7 ° south of west. 2) a) Yes, he will move, because momentum is conserved, so the product of the glove's mass and velocity (relative to the ice) has to be equal and opposite to Bill's mass times his velocity (also relative to the ice). Since the glove leaves Bill's hand with velocity v relative to his hand, and he is already moving with velocity V relative to the ice at that instant, the glove's velocity relative to the ice is v - V. 0= - m G (v-V) +M B V and so V = m G m G + M v b) Assume Bill’s mass is 100kg, the mass of the gloves 0.1kg and the velocity of the gloves 5m/s. Bills velocity will then be about V= - 0.005 m/s. If the rink is 10m in

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 3

HW_8_sol - HW 8 solutions P112 S07 1 Take east to be the...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online