# Identifying functions from relations5.pdf - 10/23/2017...

• 3
• 100% (1) 1 out of 1 people found this document helpful

This preview shows page 1 - 2 out of 3 pages.

The preview shows page 1 - 2 out of 3 pages.
10/23/2017ALEKS Robert Flen ­ 10/23/2017 2:23:26 AM EDT ­ Copyright © 2017 UC Regents and ALEKS Corporation­awh.aleks.com/alekscgi/x/Isl.exe/1o_u­IgNsIkr7j8P3jH­lv­6txjbonmD3bE8gXRAyp_X4x­dLvH­lDgTXkRpvlFYkEOmVcq0p8wYpNdThWvpQ4H63…1/31.Robert Flen ­ 10/23/2017 2:23:26 AM EDTPreCalculus / 1178 MAT200 Fall 2017 &ndash; Sinha_Durgesh_MAT200005VA016­1178­001 Â(SINHA)Identifying functions from relationsFor eachrelation, decide whether or not it is afunction.A relation is a set ofordered pairs. Each ordered pair has a "first component" and a "secondcomponent."The set of first components is thedomainof the relation.The set of second components is therangeof the relation.Afunctionis a special type of relation. In a function, no two ordered pairs have the same firstcomponent.The current problemRelation 1Relation 2Do ma inRa n g emoonpaper− 7961Do ma inRa n g e94− 67− 4doorFunctionFunctionNot a FunctionNot a FunctionRelation 3Relation 4(s, g), (y, s), (y, y), (s, s)(­8, ­8), (­7, ­8), (­1, 8), (2, ­2)FunctionFunctionNot a FunctionNot a Function

Course Hero member to access this document

Course Hero member to access this document

End of preview. Want to read all 3 pages?