MAE261 HW5 Soln'06-1

# MAE261 HW5 Soln'06-1 - smartest MAE 261 HW #5 -- DUE...

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Unformatted text preview: smartest MAE 261 HW #5 -- DUE 03-«02-06 Consider the same single-engine light general-aviation airplane, patterned after the Piper Arrow, as HW #4, which had the following characteristics: 3 = 170 a2, ‘0 m 35.4 a, e = 0.70, w n 2750113, cm, = 0.027 Engine maximum power at standard sea level is 200 hp. Assume the power of the engine is proportional to atmospheric density at altitude. The propeller efﬁciency is n = 0.75 and maximum lift coefﬁcient = 2.200. 1. Calculate the maximum and minimum equivalent airspeeds, in mph, for level flight at standard sea level, 10,000 ft and 22,000 ft. Solve for them from the power available m power required equation. 2. Calculate the atmospheric density at the absolute and service ceilings for this airplane. Then interpolate the table in Appendix B to determine the standard altitude of the absolute and service ceilings. 3. Develop a computer program or spreadsheet to calculate, tabulate and plot the maximum rate of climb (in ft/min) and minimum time to climb (minutes) as a function of altitude from standard sea level to the nearest altitude increment below the absolute ceiling. Use altitude increments of 2,000 ft. You will need a secondary vertical axis for the time to climb since its values are a different older of magnitude from the R/Cmax values. Mg; ﬁrm”, Mpg/9% w at “ire—tw- »Ec.%§ea5 «r i, . ’3 2 “An-12, Wig é fwtai .w‘viga W 3 “E: g; Y? 6 AR ,f g H - V9 3293 a; Mfg \éggngb “=3 ' \f at“ 55% it; ""3 ‘9; m" “I; AW W3}. 'W‘w" v” YE?) ﬁx? 2*: @73‘} : ngwﬁa if; H a M L VF? g :(‘*'“re)?;5§g 6%“ x W) E32536 ii? D 51:33;- —;____.___. glimb ? - _ _ __ __ ,,,L4‘303‘!§ iffHPéVS'LE'Héééiéii if f 6 1 .7 336:6; I; ,,,, ,Eiiﬁélﬁlﬁﬁéﬁi’ié 9.83%? rrrrrrrr >7 W agei . ‘ 508% “£526? " " 0509a ......... _. 0-5199: o 0012M “@693 115 ‘ ' "M'Obﬁﬁfsﬁ" * 23% in 3 "76.001104! .0.“ OE § K .wbnumw OOONN OOOON Ooomw oooww COOS. OOONV 0009. 090\$ 000\$ COO? BOON O o w! W W , . _ M W W W liv o CON 00...“. a m w .o i com min m. m. U ______ _ _ cow Doe. v ON? Oomé 26t< .33.”. .28 32:0 meoE if” 900mm oocom : 52.22 082 802. «E: w xanE 322 3% 000m o 5% 8w w w a» ‘ 0% x .m. m no 08 u .0 M u 82 83. cow? ...
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## This note was uploaded on 03/28/2008 for the course MAE 261 taught by Professor Dejarnette during the Spring '06 term at N.C. State.

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MAE261 HW5 Soln'06-1 - smartest MAE 261 HW #5 -- DUE...

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