exam 1 - Monteiro, Dalton Exam 1 Due: Sep 20 2007, 11:00 pm...

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Monteiro, Dalton – Exam 1 – Due: Sep 20 2007, 11:00 pm – Inst: McCord 1 This print-out should have 26 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. The due time is Central time. McCord 11am c = 3 × 10 8 m/s N A = 6 . 022 × 10 23 mol - 1 h = 6 . 626 × 10 - 34 J · s ν = R µ 1 n 2 1 - 1 n 2 2 R = 3 . 29 × 10 15 Hz E n = - h R n 2 h R = 2 . 18 × 10 - 18 J ψ n ( x ) = µ 2 L 1 2 sin nπx L · n = 1 , 2 , ··· E n = n 2 h 2 8 mL 2 n = 1 , 2 , 3 , ··· - ¯ h 2 2 m d 2 ψ d x 2 + V ( x ) ψ = 001 (part 1 oF 1) 10 points Set(s) oF possible values oF m are A) - 4; - 3; - 2; - 1; 0; +1; +2; +3; +4 B) - 3; - 2; - 1; 0; +1; +2; +3 C) - 2; - 1; 0; +1; +2 D) - 1; 0; +1 E) 0 Select the best choice For n = 3. 1. only E 2. only D and E 3. only C, D, and E correct 4. only B, C, D, and E 5. only C 6. only A 7. only B 8. only D 9. A, B, C, D, and E Explanation: ±or any value oF n , the possible values oF range From 0 up to ( n - 1). In turn, For any value oF , the possible values oF m range From = - , ..., 0, . .., + . Since n = 3, can be 0, 1, or 2. ThereFore when = 2, C) m = - 2; - 1; 0; +1; +2 when = 1, D) m = - 1; 0; +1 when = 0, E) m = 0 002 (part 1 oF 1) 10 points Which has the greatest number oF hydrogen atoms? 1. 100g oF a substance that is 2% H by mass 2. 5 g oF an unknown compound 3. 20 g oF hydrogen gas correct 4. 10 20 hydrogen atoms
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Monteiro, Dalton – Exam 1 – Due: Sep 20 2007, 11:00 pm – Inst: McCord 2 5. 100 g of water Explanation: 10 20 H atoms is much less than 1 mole of H atoms. 100g of water is 5.56 moles of water which would have 11.12 moles of H atoms. 5 g of an unknown substance even if it was pure hydrogen could only be 5 moles of H atoms. 20 g of hydrogen gas is 10 moles of H 2 which is 20 moles of H atoms. 100g of a substance that is 2% by mass hydrogen has 2 g of Hydrogen which is 2 moles. 20 moles of H atoms is the greatest number of atoms. 003 (part 1 of 1) 10 points For which of these elements would the electron a±nity process shown be more favorable? 1. Be + e - Be - 2. He + e - He - 3. Kr + e - Kr - 4. N + e - N - 5. C + e - C - correct Explanation: The one for C as it results in a half-full set of 2p orbitals. All of the other processes either require the electron to be placed into a new orbital of higher energy, or to be placed into an already half-full (and so already more stable) set of orbitals; either of which is unfavorable. 004 (part 1 of 1) 10 points Arrange the following in order of increasing energy. 1. infrared radiation, visible radiation, ul- traviolet radiation, microwaves, x-rays 2. microwaves, infrared radiation, visible ra- diation, ultraviolet radiation, x-rays correct 3. visible radiation, ultraviolet radiation, in- frared radiation, microwaves, x-rays 4. microwaves, ultraviolet radiation, visible radiation, infrared radiation, x-rays 5. x-rays, microwaves, visible radiation, in-
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exam 1 - Monteiro, Dalton Exam 1 Due: Sep 20 2007, 11:00 pm...

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