PHYS 1415 TEST ONE.docx

# PHYS 1415 TEST ONE.docx - COLLISION SHEET EQUATIONS...

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COLLISION SHEET - EQUATIONS - Conservation of momentum: Net momentum BEFORE COLLISION = Net momentum AFTER COLLISON - Momentum = Mass X Velocity - Kinetic Energy = ½ Mass* Velocity 2 (½MV 2 ) - With inelastic equations, when you need velocity, take the total momentum / by the masses. (M 1 +M 2 ) (Velocity) = Total Momentum - Do not forget to add in direction (+ or – X) -Half the mass = twice the speed, double the mass = half the speed __________________________________ TEST 1 STUDY PROBLEMS - EQUATIONS - Velocity = FINAL POSITION INITIALPOSIT TIME - Change in Position = Final Position – Initial Position - Speed = DISTANCE ( x ) TIME ( t ) - Acceleration = CHANGE OF VELOCITY TIME INTERVAL - 1 KG = 10 Newton’s - Gravity = 10 m/s 2 - Work = Force X Distance - Power = WORK DONE TIME INTERVAL - The unit for Power is Watts . -Potential Energy (PE) = Mass X Acceleration due to gravity X Height (PE = mgh _______________________________ KE, PE, KINEMATIC EQUATIONS, ENERGY, FREE FALL - EQUATIONS -Time to max height = v O /g (Time up) -Time it takes to fall Y 0 meters = 2 Y g - Position : Y = Y 0 + V 0 t + ½at 2 V = V 0 + gt V 2 = V 0 2 + 2a∆y (∆y = y 1 – y 2 ) - Free Fall Motion Equations : Distance : Y = Y 0 + V 0 t – ½ gt 2 Velocity : V = V 0 – gt - Projectile motion: a y = -g = 10 m/s ^ y __________________________________

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COLLISION SHEET - EXAMPLES - If a freight engine that has a mass of 5000 KG moving at 12 M/S connects with a freight car that has a mass of 1000 KG sitting at rest, what is the final velocity of the coupled train?

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